Answer:
Characteristic equation:

Eigen values:

Step-by-step explanation:
We are given the matrix:
![\displaystyle\left[\begin{array}{ccc}-14&-6&6\\28&12&-4\\0&0&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-14%26-6%266%5C%5C28%2612%26-4%5C%5C0%260%264%5Cend%7Barray%7D%5Cright%5D)
The characteristic equation can be calculated as:

We follow the following steps to calculate characteristic equation:
![=det\Bigg(\displaystyle\left[\begin{array}{ccc}-14&-6&6\\28&12&-4\\0&0&4\end{array}\right]-\lambda\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]\Bigg)\\\\= det\Bigg(\displaystyle\left[\begin{array}{ccc}-14-\lambda&-6&6\\28&12-\lambda&-4\\0&0&4-\lambda\end{array}\right]\Bigg)\\\\=(-14-\lambda)[(12-\lambda)(4-\lambda)]+6[28(4-\lambda)]-6[(28)(0)-(12-\lambda)(0)]\\\\= -\lambda^3 + 2\lambda^2 + 8\lambda](https://tex.z-dn.net/?f=%3Ddet%5CBigg%28%5Cdisplaystyle%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-14%26-6%266%5C%5C28%2612%26-4%5C%5C0%260%264%5Cend%7Barray%7D%5Cright%5D-%5Clambda%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D%5CBigg%29%5C%5C%5C%5C%3D%20det%5CBigg%28%5Cdisplaystyle%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-14-%5Clambda%26-6%266%5C%5C28%2612-%5Clambda%26-4%5C%5C0%260%264-%5Clambda%5Cend%7Barray%7D%5Cright%5D%5CBigg%29%5C%5C%5C%5C%3D%28-14-%5Clambda%29%5B%2812-%5Clambda%29%284-%5Clambda%29%5D%2B6%5B28%284-%5Clambda%29%5D-6%5B%2828%29%280%29-%2812-%5Clambda%29%280%29%5D%5C%5C%5C%5C%3D%20-%5Clambda%5E3%20%2B%202%5Clambda%5E2%20%2B%208%5Clambda)

To obtain the eigen values, we equate the characteristic equation to 0:
![p(\lambda) = -\lambda^3 + 2\lambda^2 + 8\lambda = 0\\-\lambda(\lambda^2-2\lambda-8) = 0\\-\lambda(\lambda^2-4\lambda+2\lambda-8) = 0\\-\lambda[(\lambda(\lambda-4)+2(\lambda-4)] = 0\\-\lambda(\lambda+2)(\lambda-4) = 0 \\\lambda_1 = 0, \lambda_2 = -2, \lambda_3= 4](https://tex.z-dn.net/?f=p%28%5Clambda%29%20%3D%20-%5Clambda%5E3%20%2B%202%5Clambda%5E2%20%2B%208%5Clambda%20%3D%200%5C%5C-%5Clambda%28%5Clambda%5E2-2%5Clambda-8%29%20%3D%200%5C%5C-%5Clambda%28%5Clambda%5E2-4%5Clambda%2B2%5Clambda-8%29%20%3D%200%5C%5C-%5Clambda%5B%28%5Clambda%28%5Clambda-4%29%2B2%28%5Clambda-4%29%5D%20%3D%200%5C%5C-%5Clambda%28%5Clambda%2B2%29%28%5Clambda-4%29%20%3D%200%20%5C%5C%5Clambda_1%20%3D%200%2C%20%5Clambda_2%20%3D%20-2%2C%20%5Clambda_3%3D%204)
We can arrange the eigen values as:

Total = Principal * ((1 + rate/n)^(n*years)
Total = 3,000 * (1.04)^20
Total =
3,000 *<span>
<span>
<span>
2.191123143
</span>
= </span></span>
<span>
<span>
<span>
6,573.37</span></span></span>
So, he will have to add (7,000 - <span>6,573.37) =
$ 426.63
answer is b
Here's a calculator to check your work http://www.1728.org/compint.htm
</span>
Answer:
9x + 6
Step-by-step explanation:
<u>Step 1: Distribute</u>
5x + (x + 6) + 3x
5x + x + 6 + 3x
<u>Step 2: Combine like terms</u>
5x + x + 6 + 3x
9x + 6
Answer: 9x + 6
If the exchange rate is $1.46 and you are exchanging $100, you will receive 146 pounds.