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statuscvo [17]
4 years ago
14

HURRY I'LL PICK A BRAINLIEST!!!

Mathematics
2 answers:
Free_Kalibri [48]4 years ago
6 0
K = 4a+9ab
k = a(4+9b)
k/(4+9b) = a
a = k/(4+9b)

None of the answer choices match what I got, so I'm thinking there's a typo. Perhaps choice A is supposed to say a = k/(4+9b) since that seems like the closest
Ber [7]4 years ago
6 0

Answer:

Step-by-step explanation:

A

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PLEASE HELP!!!!<br><br>Math Homework
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You need to add the second number and the answer to get your answer

A. 2

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3 years ago
Evaluate when w-k when w= -17 and k= -5
OLEGan [10]

How it's evaluated:


(1) w - k = -7 - -5

(2) -17 - -5= = -17 + (-15)

(3) -17 + (-15) = -2


First step is change W and K and change it into it's correct number.

Second step is change the subtraction sign to it's opposite.

Third step is subtract -17 and (-15) which would give you -2

3 0
4 years ago
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Which set of side lengths can be used to construct a triangle?
galina1969 [7]
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6 0
4 years ago
A principal wants to know if students at a particular high school are in favor of a new dress code at their school. The principa
svp [43]

Answer:

student randomly selected from a list of all students at the school

8 0
3 years ago
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If a car’s speed is 70 miles per hour on a road surface with a drag factor of 0.50 and with a breaking efficiency of 85% (n = .8
hichkok12 [17]

Answer:

About 384.3 feet

Step-by-step explanation:

The formula for that is given by,

S= \sqrt{30 \times d \times f \times n}

Where,

S is the speed of the car

d is the distance of skid

f is the drag factor for the road surface

n is breaking efficiency as percentage

Putting the values we get,

S^2=  30 \times d \times f \times n

d= \frac{S^2}{30 \times f \times n}

d = \frac{70^2}{30 \times 0.50 \times 0.85} = 384.3 feet

So the length of skid marks would be 384.3 feet.

8 0
3 years ago
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