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JulsSmile [24]
2 years ago
12

In an isosceles triangle, one of the equal interior angles is equal to the adjacent exterior

Mathematics
1 answer:
yarga [219]2 years ago
5 0

Answer:

Step-by-step explanation:

can you show a picture?

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Find the product 2x(-8)x(-9)
Elza [17]
2x(-8)x(-9)

2x8x9

16x9=144
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3 years ago
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Describe the pattern for the powers of 10. Write the values of 10*1and 10*0<br> in the table.
blagie [28]

Answer:

here

Step-by-step explanation:

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3 0
2 years ago
(06.05) Neil is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect? graph of the function f of
schepotkina [342]
Given the stated equation we know that that quadratic formula has 2 as its degree. This meats it has 2 roots. A linear equation has a degree of 1. A linear equation has 1 root. To know if they intersect, the must have one root in common. To know this, solve the two equation simultaneously. If they result to an answer then they intersect. 
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3 years ago
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If s is an increasing function, and t is a decreasing function, find Cs(X),t(Y ) in terms of CX,Y .
Sedbober [7]

Answer:

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

Step-by-step explanation:

Let's introduce the cumulative distribution of (X,Y), X and Y :

F(X,Y)(x,y)=P(X≤x,Y≤y)

  • FX(x)=P(X≤x)
  • FY(y)=P(Y≤y).

Likewise for (s(X),t(Y)), s(X) and t(Y) :

F(s(X),t(Y))(u,v)=P(s(X)≤u

  • t(Y)≤v)
  • Fs(X)(u)=P(s(X)≤u)
  • Ft(Y)(v)=P(t(Y)≤v).

Now, First establish the relationship between F(X,Y) and F(s(X),t(Y)) :

F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

Now, to transform this into a statement about copulas, note that

C(X,Y)(a,b)=F(X,Y)(F−1X(a), F−1Y(b))

Thus, plugging x=F−1X(a) and y=F−1Y(b) into our previous formula,

we get

F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

Note that

Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

and likewise

Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

Combining all results we obtain for the relationship between the copulas

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

7 0
3 years ago
1. Refer to the equation 3x − 5y = 15. (a) Create a table of values for at least 4 points. Show your work on how you found the v
Ann [662]

Answer:

(0, 3 ), (5, 0), (10, -3), (15, -6)

Step-by-step explanation:

3x − 5y = 15

-5y = 3x + 15

y = -\frac{3}{5} x + 3

Point 1:  (0, 3 )

  y = -3/5(0) + 3

  y = 0 + 3

  y = 3

 

  Validate:

   3 = -3/5(0) + 3

   3 = 3

Point 2:  (5, 0)

  y = -3/5(5) + 3

  y = -3 + 3

  y = 0

  Validate:

   0 = -3/5(5) + 3

   0 = 0

Point 3:  (10, -3)

  y = -3/5(10) + 3

  y = -6 + 3

  y = -3

  Validate:

   -3 = -3/5(10) + 3

   -3 = -3

Point 4:  (15, -6)

  y = -3/5(15) + 3

  y = -9 + 3

  y = -6

 Validate:

   -6 = -3/5(15) + 3

   -6 = -6

6 0
3 years ago
Read 2 more answers
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