2 years ago

Which expression is equivalent to (8^2)^-4

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

6 0

Answer:

C: $\frac{1}{8*8*8*8*8*8*8*8}$

Step-by-step explanation:

$a^{-n} = \frac{1}{a^n}$

Since a = $8^2$ :

$(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}$

Since n = 4 :

$(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}$

You might be interested in

The base of a triangle is 9/4 times of its height. If the area of triangle is 144 cm2. Find the height and the base.

Mazyrski [523]

Step-by-step explanation:

Given that the base of triangle is 9/4 times of its height . And area is 144 cm² . Let the height be h , then its base be 9h/4 .

• According to Question :-

$\tt\to Area_{(\triangle)}=\dfrac{base\times height}{2}\\\\\tt\to 144cm^2 = \dfrac{9h\times h}{4\times 2 } \\\\\tt\to h^2 =\dfrac{12\times 12 \times 2 \times 2 }{3\times 3 }\\\\\tt\to h =\sqrt{\dfrac{12\times 12 \times 2 \times 2 }{3\times 3 }}\\\\\tt\to h =\dfrac{(12)(2)}{3} \\\\\tt\to \boxed{\orange{\tt h = 8 cm }}$