Question

Which expression is equivalent to (8^2)^-4

Answer 1

Answer:

C: $\frac{1}{8*8*8*8*8*8*8*8}$

Step-by-step explanation:

$a^{-n} = \frac{1}{a^n}$

Since a = $8^2$ :

$(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}$

Since n = 4 :

$(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}$