The paper is 16 cm by 34 cm to start with, so we started with area
.. (16 cm)*(34 cm) = 544 cm^2
A circle of diameter 16 cm has been removed. The area of that circle is
.. π*(d/2)^2 = 3.14*(16 cm/2)^2 = 200.96 cm^2
Then the area of the paper that remains is
.. 544 cm^2 -200.96 cm^2
.. = 343.04 cm^2
<span>An obtuse triangle will have one and only one obtuse angle. </span>
<span>The other two angles are acute angles.</span>
<span>The sum of the two angles other than the obtuse angle is less than 90º.<span /></span>
<span><span>The side opposite to the obtuse angle is the longest side of the triangle.</span></span>
<span><span>
</span><span>The points of concurrency, the Circumcenter and the Orthocenter lie outside of an obtuse triangle, while Centroid and Incenter lie inside the triangle.
</span></span>
Answer:
You would start with 00.-6 and stop a-5954
Step-by-step explanation:
Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
