Data Set: 13, 1, 18, 20, 18 • Mean = Median = • Mode = • Range - • Outlier -
2 answers:
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Answer:
(a) The probability that a randomly selected time interval between eruptions is longer than 82 minutes is 0.3336.
(b) The probability that a random sample of 13-time intervals between eruptions has a mean longer than 82 minutes is 0.0582.
(c) The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes is 0.0055.
(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.
(e) The population mean must be more than 72, since the probability is so low.
Step-by-step explanation:
We are given that a geyser has a mean time between eruptions of 72 minutes.
Also, the interval of time between the eruptions be normally distributed with a standard deviation of 23 minutes.
(a) Let X = <u><em>the interval of time between the eruptions</em></u>
So, X ~ N()
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean time = 72 minutes
= standard deviation = 23 minutes
Now, the probability that a randomly selected time interval between eruptions is longer than 82 minutes is given by = P(X > 82 min)
P(X > 82 min) = P( >
) = P(Z > 0.43) = 1 - P(Z
0.43)
= 1 - 0.6664 = <u>0.3336</u>
The above probability is calculated by looking at the value of x = 0.43 in the z table which has an area of 0.6664.
(b) Let = <u><em>sample mean time between the eruptions</em></u>
The z-score probability distribution for the sample mean is given by;
Z = ~ N(0,1)
where, = population mean time = 72 minutes
= standard deviation = 23 minutes
n = sample of time intervals = 13
Now, the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 minutes is given by = P( > 82 min)
P( > 82 min) = P(
>
) = P(Z > 1.57) = 1 - P(Z
1.57)
= 1 - 0.9418 = <u>0.0582</u>
The above probability is calculated by looking at the value of x = 1.57 in the z table which has an area of 0.9418.
(c) Let = <u><em>sample mean time between the eruptions</em></u>
The z-score probability distribution for the sample mean is given by;
Z = ~ N(0,1)
where, = population mean time = 72 minutes
= standard deviation = 23 minutes
n = sample of time intervals = 34
Now, the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes is given by = P( > 82 min)
P( > 82 min) = P(
>
) = P(Z > 2.54) = 1 - P(Z
2.54)
= 1 - 0.9945 = <u>0.0055</u>
The above probability is calculated by looking at the value of x = 2.54 in the z table which has an area of 0.9945.
(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.
(e) If a random sample of 34-time intervals between eruptions has a mean longer than 82 minutes, then we conclude that the population mean must be more than 72, since the probability is so low.
Answer:
Abel receives $60, and Cedric receives $120
Step-by-step explanation:
Let Abel's share = A
Let Cedric's share = C
we are given the following
A + C = 180 - - - - - (1) (Abel and Cedric will share a total of $180)
(Abel will receive half as much as Cedric. )
from equation 2:
putting this value of C in eqn (3) into eqn (1)
A + (2A) = 180
3A = 180
∴ A = 180 ÷ 3 = 60
to find C, let us replace the value of A in eqn (3) with 60
C = 2A - - - - (3)
C = 2 × 60
C = 120
Therefore, Abel receives $60, and Cedric receives $120