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m_a_m_a [10]
3 years ago
5

Which is the greatest common factor of the expression below? 32a²b2 + 36a²c2 – 16ab3

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

Step-by-step explanation:

32a²b²  = 2 * 2*2*2*2 * a² * b²

36a²c² = 2 * 2 * 3 * 3 * a² * c²

16ab³  = 2 * 2 * 2* 2 * a * b³

Greatest common factor =  2*2*a = 4a

32a²b² + 36a²c² - 16ab³ = 4a*(8ab² + 9ac² - 4b³)

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well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

4 0
2 years ago
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Answer:

4.5yards

Step-by-step explanation:

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