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statuscvo [17]
3 years ago
13

Jolie sends between 22 and 23 text messages per day. Each text message costs $0.89. Suppose Jolie's cellular bill spans a period

of 6 weeks. Which is a reasonable amount that she would spend on text messages on one cellular bill? A. $135 B. $9,108 C. $945 D. $158
Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer:

C. $945

Step-by-step explanation:

Cost of 1 cellular bill = (number of text msgs per day) x (cost per text msg) x (number of days in billing period)

in this case, it is given that :

cost per text msg = $0.89

number of texts per day = 22 or 23

billing cycle = 6 weeks = 6 x 7 = 42 days

hence,

Cost of 1 cellular bill = (22 or 23) x $0.89 x 42 days

if she sends 22 messages,

Cost of 1 cellular bill = (22) x $0.89 x 42 days= $822.36

if she sends 23 messages,

Cost of 1 cellular bill = (2) x $0.89 x 42 days= $859.74

if we compare thse 2 numbers that we have calculated with the choices, the closest match would be C. $945. The rest are just too far away in comparison.

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The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 1000 vo
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Answer:

z=\frac{0.54 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=2.530  

p_v =P(z>2.530)=0.0057  

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

\hat p=0.54 estimated proportion of residents that favored the annexation

p_o=0.5 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.54 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=2.530  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.530)=0.0057  

7 0
3 years ago
BRAINLIEST
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Answer:

B. 1 1/3

Step-by-step explanation:

\frac{5}{6} + \frac{3}{6} = \frac{8}{6}

\frac{8}{6} = \frac{4}{3}

three can go into 4 once, so we have a whole number of 1 and a leftover 1/3.

= 1\frac{1}{3}

hope this helps :)

4 0
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Lapatulllka [165]

Answer:

1/2 of an answer is zero answer.

Step-by-step explanation:

yeah :)

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