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GenaCL600 [577]
2 years ago
8

5=97 find 2 and 4....................,,..,...

Mathematics
1 answer:
makvit [3.9K]2 years ago
8 0

Answer:

∠ 2 = ∠ 4 = 83°

Step-by-step explanation:

∠ 2 and ∠ 5 are same- side interior angles and sum to 180° , that is

∠ 2 + 97° = 180° ( subtract 97° from both sides )

∠ 2 = 83°

∠ 2 and ∠ 4 are vertical angles and are congruent, then

∠ 4 = 83°

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What is the equation of a quadratic graph with a focus of (-4,17/8) and a detric of y=15/8 answer
Nonamiya [84]

keeping in mind that the vertex is between the focus point and the directrix, in this cases we have the focus point above the directrix, meaning is a vertical parabola opening upwards, Check the picture below, which means the "x" is the squared variable.

now, the vertical distance from the focus point to the directrix is \bf \cfrac{17}{8}-\cfrac{15}{8}\implies \cfrac{2}{8} , which means the distance "p" is half that or 1/8, and is positive since it's opening upwards.

since the vertex is 1/8 above the directrix, that puts the vertex at \bf \cfrac{15}{8}+\stackrel{p}{\cfrac{1}{8}}\implies \cfrac{16}{8}\implies 2 , meaning the y-coordinate for the vertex is 2.

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\bf \begin{cases} h=-4\\ k=2\\ p=\frac{1}{8} \end{cases}\implies 4\left(\frac{1}{8} \right)(y-2)=[x-(-4)]^2\implies \cfrac{1}{2}(y-2)=(x+4)^2 \\\\\\ y-2=2(x+4)^2\implies \blacktriangleright y = 2(x+4)^2+2 \blacktriangleleft

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An athletic director pays $90 for 12 sun visors for the softball team. how much will the athletic director pay to buy 15 more su
satela [25.4K]

An athletic director pays $90 for 12 sun visors for the softball team. The rate per sun visor is equal to $90 / 12 sun visor = $ 7.5 per sun visor. So the athletic director should pay ($ 7.5 per sun visor)*(15 sun visor) = $ 112.5

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3 years ago
Read 2 more answers
JUST ANSWER PLEASE!!! QUICK
jeka57 [31]

Answer:

<u>Options 1 and 3</u>

Step-by-step explanation:

We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given:  the solution for the following system is (2,9)

Px + Qy = R  ⇒(1)

Tx + Uy = V  ⇒(2)

We will check which system of equation has the same solution.

<u>System A)</u>  Px + Qy = R

                  (P+T)x + (Q+U)y = R+V  ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

<u>System B)</u> Px + Qy = R

                 (P+2T)x + (Q+2U)y = R-2V  ⇒(4)

By multiplying equation (2) by 2 and add with equation (1), we will get:

 (P+2T)x + (Q+2U)y = R+2V

Which is not the same as equation (4)

So, system B has not the same solution (2,9)

<u>System C)</u> (T-P)x + (U-Q)y = V-R  ⇒(5)

                  Tx + Uy = V  

By multiplying equation (1) by -1 and add with equation (2), we will get the equation (5)

So, system C has the same solution of (2,9)

<u>System D)</u> (T-P)x + (Q+U)y = V-R  ⇒(6)

                  Tx + Uy = V  

We cannot get equation (6) by the same operation over equation (1)

Note the coefficient of x and y⇒ (T-P) and (Q+U)

They must be (T+P) and (Q+U) <u>OR </u>(T-P) and (Q-U)

So, system D has not the same solution of (2,9)

<u>System E)</u> (5T-P)x + (5U-Q)y = V-5R ⇒ (6)

                  Tx + Uy = V  

By subtract equation (1) from 5 times equation (2), we will get:

(5T-P)x + (5U-Q)y = 5V-R

Which is not the same as equation (6)

So, system E has not the same solution (2,9)

As a conclusion, the systems which have the same solution are:

<u>Options 1 and 3</u>

5 0
3 years ago
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