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Goshia [24]
4 years ago
5

9. A rectangle has a length of 10 ft. and a width of 6 ft. What's the perimeter? A. 26 ft. B. 60 ft. C. 16 ft. D. 32 ft.

Mathematics
1 answer:
olga_2 [115]4 years ago
8 0
The answer would be D) 32 ft

<em>Explanation:
</em>Since you're trying to find the perimeter you need to add up each side.
The problem gives away that the length is 10 ft and that the width is 6 ft.
In order to find the total length you need to add 10 + 10, you should get 20.
Now you do the same to the width, 6 + 6 = 12.

To find the total you need to add 12 and 20 together,
12 + 20 = 32
So the perimeter = 32


Hope this helped, have a great day~
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Find the value of the determinant using the method of expansion by minors; expand on the third row
valkas [14]

For the matrix

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the determinant using the method of expansion by minors, expanding on the third row is:

\det \begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}=a_{31}\det \begin{bmatrix}{a_{12}} & {a_{13}} & {} \\ {a_{22}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}-a_{32}\det \begin{bmatrix}{a_{11}} & {a_{13}} & {} \\ {a_{21}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}+a_{33}\det \begin{bmatrix}{a_{12}} & {a_{12}} & {} \\ {a_{22}} & {a_{22}} & {} \\ {} & {} & {}\end{bmatrix}

Answer:

First, we compute the determinants of the minors:

\begin{gathered} \det \begin{bmatrix}{0} & {4} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=0+4=4, \\ \det \begin{bmatrix}{1} & {4} & {} \\ {1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=3-4=-1, \\ \det \begin{bmatrix}{1} & {0} & {} \\ {1} & {-1} & {} \\ {} & {} & {}\end{bmatrix}=-1-0=-1. \end{gathered}

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1 year ago
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seraphim [82]

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2 years ago
<img src="https://tex.z-dn.net/?f=%28%20-%207x%20%2B%201%29%20-%20%284x%20%2B%205%29" id="TexFormula1" title="( - 7x + 1) - (4x
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Answer:

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Step-by-step explanation:

We are first going to distribute to get rid of the ( ):

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