I could use some help answering this math problem!!

Find the area of each shape by decomposing each shape into rectangle and/or triangle.

avanturin [10]

Remark

You don't have to decompose the second one, and it is better if you don't. Just find the area as you probably did: use the formula for a trapezoid. You have to assume that the 6cm line hits the 2 bases at right angles for each of them, otherwise, you don't know the height. So I'm going to assume that we are in agreement about the second one.

Problem One

The answer for this one has to be broken down and unfortunately, you answer is not right for the total area, although you might get 52 for the triangle. Let's check that out.

Triangle

Area = 1/2 * b * h

base = 16 cm

h = 10 - 4 = 6

Area = 1/2 * 16 * 6

Area = 48

Area of the Rectangle

Area = L * W

L = 16

W = 4

Area = L * W

Area = 16 * 4

Area = 64

Total Area

Area = 64 + 48

Area = 112 of both figures <<<< Answer

3 0

2 years ago

The graph of f(x)=√x Is shifted four units up and five units to the right. What is the equation of the resulting graph?

RoseWind [281]

A vertical shift adds/subtracts a constant to/from every y-coordinate while leaving the x-coordinate unchanged. A horizontal shift adds/subtracts a constant to/from every x-coordinate while leaving the y-coordinate unchanged. Vertical and horizontal shifts can be combined into one expression.

Shifting up or to the right means add

Shifting down or to the left means subtract

the 3rd option is the correct one

7 0

1 year ago

Give each answer as mixed number in simplest form

telo118 [61]

Step-by-step explanation:

$= \frac{1}{2} + ( - 5 \frac{9}{10} )$

$= \frac{1}{2} - 5 \frac{9}{10} \\$

$= \frac{1}{2} - \frac{5 \times 10 + 9}{10} \\$

$= \frac{1}{2} - \frac{59}{10} \\$

$= \frac{1}{2} \times \frac{5}{5} - \frac{59}{10} \\$

$= \frac{5}{10} - \frac{59}{10} \\$

$= \frac{5 - 59}{10} \\$

$= - \frac{54}{10} \\$

$= - \frac{27}{5} \\$

6 0

2 years ago

Read 2 more answers

You have two coupons, one is for $25 off and the other is for 25% off. When would you use the $25 off coupon? When would you use

Brut [27]

Answer:

If I had two coupons, one for $ 25 off and the other for 25% off, to determine when I would use the $ 25 off coupon and when I would use the 25% off coupon, and when it would not matter which coupon I would use, I must carry out the following reasoning:

The $ 25 off coupon is a flat coupon, that is, it does not adapt to the price of the thing to be paid, but rather maintains its value constantly. Therefore, its utilization will be higher if those $ 25 represent a high value compared to the initial price of the product: if the thing is worth $ 50, a $ 25 off coupon represents half its value, while if the thing is worth $ 500, that same coupon will only represent 5% of it. Therefore, I would use the coupon for things that are worth between $ 25 and $ 99.

Instead, the 25% off coupon is a variable coupon, which is adapted according to the value of the product. In other words, a discount will always be made for 25% of said value: if the product is worth $ 80, the discount will be $ 20 (80 x 0.25), while if the product is worth $ 1,000, the discount will be $ 250 (1000 x 0.25 ). Therefore, I would use the coupon for products with a price greater than $ 100, that is, from $ 101 and up.

Finally, since 25% of $ 100 is $ 25, if you buy something of that value, it would be indistinct to use either of the two coupons.

8 0

3 years ago

Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error