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mafiozo [28]
3 years ago
5

Help me please, please

Mathematics
1 answer:
kondaur [170]3 years ago
4 0
5x^2 - 24x + 8 is your answer to this equation
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On a number line, show all points whose coordinates satisfy the following inequalities: |x−20|<5
VLD [36.1K]

Answer:

On the number line integers from 16 to 24 is the answer.

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2 years ago
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Please help me need to revise for a testtt!!!!
LUCKY_DIMON [66]
Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so

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group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
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2 years ago
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tatyana61 [14]
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20 points!! Solve this system of lineal equations.separate the x- and y- values with a comma
Zielflug [23.3K]
Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
Divide equation 1 by -17:{x+0 y = 4 | (equation 1)0 x+y = 1 | (equation 2)
Collect results:Answer:  {x = 4 {y = 1


Please note the { are supposed to span over both equations but it interfaces doesn't  allow it. Please see attachment for clarification.

7 0
3 years ago
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