Question

If a 10-mm-wide snowflakes shaped like regular hexagons were to tile a 40 mm wide by 30 mm tall area (with slight gaps at the edges), how many snowflakes would there be?

Answer 1

Answer:

The number of snowflakes = 4

Step-by-step explanation:

The area of a regular hexagons of wide length a = $\frac{3\sqrt{3}}{2} a^2$

if a = 10

∴ Area of the hexagons = $\frac{3\sqrt{3} }{2} *10^2 = 259.81$ mm²

The area of a 40 mm wide by 30 mm tall = 40*30 = 1200 mm²

∴ The number of snowflakes = 1200/259.81 = 4.6188

Take the integer number.

So, The number of snowflakes = 4