The answer would be $26.45.
What you do is on a calculator: 115 x 23%
Hope this helps :)
Answer:
15 hours.
Step-by-step explanation:
20 can be divided into quarters, 3 quarters is 15/20 hours.
-6×-6=36
f-34=36
34+36=70
f=70
Answer:
Margin of error for a 95% of confidence intervals is 0.261
Step-by-step explanation:
<u>Step1:-</u>
Sample n = 81 business students over a one-week period.
Given the population standard deviation is 1.2 hours
Confidence level of significance = 0.95
Zₐ = 1.96
Margin of error (M.E) = 
Given n=81 , σ =1.2 and Zₐ = 1.96
<u>Step2:-</u>
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On calculating , we get
Margin of error = 0.261
<u>Conclusion:-</u>
Margin of error for a 95% of confidence intervals is 0.261
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Answer:
Data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20}
Step-by-step explanation:
The question is:
Which data set has the greatest spread for the middle 50% of its data
We have given the data sets:
{18,13,22, 17, 21, 24}
{17,19,22,26,17,14}
{13,17,12,21, 18,20}
{18,21,16,22,24,15}
To find the greatest spread for the middle we need to find the IQR for all the data sets and check which one is highest.
So,
For the first set: 22-17 = 5
For the second: 22-17 = 5
For the third set = 20-13 = 7
For the fourth set = 22-16 = 6
Since data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20} ....