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3 years ago

How to calculate this?

Mathematics

1 answer:

Alona [7]3 years ago

3 0

you can use calcutaor and write all the number by order than find the mean,median,mode,range.

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What is the lcm of 4 and 5

timama [110]

Answer:

Step-by-step explanation:

4 * 1 = 4 5 * 1 = 5

4 * 2 = 8 5 * 2 = 10

4* 3 = 12 5 * 3 = 15

4 * 4 = 16 5 * 4 = 20

4 * 5 = 20

they both go into 20 equally. there is no number lower than 20 that they both go into

8 0

3 years ago

A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against th

lys-0071 [83]

Answer:
let x=rate of the rowing team in still water
x+4=rate of the rowing team with current
x-4=rate of the rowing team against current
travel time=distance/rate
..
90%2F%28x%2B4%29=10%2F%28x-4%29
90x-360=10x+40
80x=400
x=5  rate of the rowing team in still water=5 mph

4 0

3 years ago

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago

Find the Area of ze Trapezoid

Elina [12.6K]

A=a+b/2·h=9+4/2·3.5=22.75

Hoped I helped!

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4 years ago

What is the slope, x intercept, y intercept for this question: 1/3x+ 1/2y= 9

Sergeeva-Olga [200]

Hope this helps you 3y=54-2

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3 years ago