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Nat2105 [25]
3 years ago
14

4/175.68 show ur please

Mathematics
2 answers:
matrenka [14]3 years ago
5 0
175.68 divided 4 is 43.92 because
175.68
-16
15
-12
36
-36
08
-8
0

LekaFEV [45]3 years ago
3 0
4/175.68 = 43.92
First you put 4 above the 17 then you should get 16 and you subtract that and you will get 1 the add the 5 and you will get 15. Then you put 3 over the 5 and you should get 12 then you subtract 15 by 12 and you should get 3 then add the 6 and you should have 36. Then you put a 9 over the 6 and you should get 36 and you subtract that and you get 0. Then you put a 2 over the 8 and you should get 8 The you subtract that and you get 0 so your final answer should be 175.68/4 = 43.92
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Sam needs a web designer. Designer A is offering her services for an initial $450 in addition to $105 per hour. Designer B is of
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Answer:

After 5 hours the two would charge the same amount of money.

Step-by-step explanation:

Designer A:  $450 + ($105/hr)x, where x is the number of hours worked;

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Equating these two formulas, we get:

$450 + ($105/hr)x = $725 + ($50/hr)x

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Dividing both sides by $55 yields the number of hours worked:

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A random sample of 100 teletype operators indicates that their salaries fluctuate quite a bit. The sample Standard deviation of
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Answer:

\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}

80.341 \leq \sigma^2 \leq 128.495

Now we just take square root on both sides of the interval and we got:

8.963 \leq \sigma \leq 11.336

Step-by-step explanation:

Data given and notation

s=10 represent the sample standard deviation

\bar x represent the sample mean

n=100 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=100-1=99

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,99)" "=CHISQ.INV(0.95,99)". so for this case the critical values are:

\chi^2_{\alpha/2}=123.225

\chi^2_{1- \alpha/2}=77.046

And replacing into the formula for the interval we got:

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