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barxatty [35]
3 years ago
9

gn="absmiddle" class="latex-formula">
Mathematics
1 answer:
Arturiano [62]3 years ago
8 0

D=b^2-4ac\\D=4^2-4(4)(1)\\D=16-16\\D=0

Meaning there's only 1 real root, complete the square and you get the answer.

(x+y)^2=x^2+2xy+y^2

We're going to use this formula, so if x² = 4x² then x = 2x

and if y² = 1 then y = 1

Straight to formula

(2x+1)^2=0\\x=-\frac{1}{2}

Because (2x+1)² is basically (2x+1)(2x+1), we get the same value of x.

So the answer is x = -1/2

(When D>0, there are 2 real roots.)

(When D=0, there are only 1 real root.)

(When D<0, there are no real roots, but 2 complex roots.)

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