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kiruha [24]
3 years ago
9

The following points are rotated about the origin through 90° in clockwise direction. Find the new coordinates,

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

C

Maybe it is B or A as the answer.

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sveta [45]
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.

b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
4 0
3 years ago
A family on a trip budgets $1,000 for meals and gasoline. If the price of a meal for the family is $50 and if gasoline costs $3.
galben [10]

Answer:

They can buy 13meals if they buy 100 gallons of gasoline.

Step-by-step explanation:

3.50 PER gallon so 1 gallon is $3.50

if they buy 100 gallons you have to multiply 3.50 by 100 which gives you 350. you subtract 350 from 1000 so 1000-350 and get 650. now, you divide 650 by 50 because each meal is $50. And you get 13 so there you have it.

3 0
3 years ago
What is the answer. Evalute (2/3)2. Thank you
polet [3.4K]

Answer:

4/3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
a circular oil slick is expanding at a rate of 2m^2/h. Find the rate at which it's diameter is expanding when it's radius is 1.5
aleksandrvk [35]

Answer:  \frac{4\pi}{3} \text{ meter per hour}

Step-by-step explanation:

The circular oil slick is expanding at a rate of  2 m^2/h

Let A be the area of the circular oil slick,

So, the changes in  A with respect to time (t),

\frac{dA}{dt} = 2

\frac{d(\pi r^2)}{dt} = 2

2\pi r\frac{dr}{dt} = 2

\frac{dr}{dt} = \frac{1}{\pi r}  

Also, the change in diameter with respect to time(t),

\frac{d}{dt} (2 r) = 2 \frac{dr}{dt}

\frac{d}{dt} (2 r) = 2 \times \frac{1}{\pi r}

\frac{d}{dt} (2 r) = \frac{2}{\pi r}

For r = 1.5 m,

\frac{d}{dt} ( 2 r)]_{r=1.5} = \frac{2}{\pi \times 1.5}=\frac{20}{\pi \times 15}=\frac{4\pi }{3}\text{ meter per hour}




7 0
3 years ago
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