The following points are rotated about the origin through 90° in clockwise direction. Find the new coordinates,

Suppose you have to use right-triangle trigonometry to find the apothem of a regular polygon. Which is greater, the apothem or t

asambeis [7]

The apothem represents one side of the right triangle to be solved. Specifically, it represents the height of the triangle.
The radius of the polygon represents the hypotenuse of the right triangle that is going to be solved.
Therefore, we can infer that the radius of the polygon is greater than the apothem because the hypotenuse is greater than all sides of a triangle.
Answer:
the radius of the polygon is greater

8 0

2 years ago

A boy purchased (bought) a party-length sandwich 51 in. long. He wants to cut it into three pieces so that the middle piece is

shepuryov [24]

Answer:

Step-by-step explanation:

we have a 51 in sandwich

let a piece be x

we have x= shorter piece

another piece is x+6

another piece (x+6)-9=x-3

x+x+6+x-3=51

3x=51-3

3x=48

x=48/3=16

x=16, longer piece is 16+6=22, shorter piece =10

6 0

2 years ago

Help pls! It’s due soon

Juliette [100K]

Answer:

x1 = -8 and x2 = 9?

6 0

3 years ago

Read 2 more answers

2x+3y=1 and y=-2 - 9 solve using linear combination method. Please explain steps.

kaheart [24]

Answer:

$x=17$

Step-by-step explanation:

$2x+3y=1$

$y=-2-9$

In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value, $y$ . In this case, we need to isolate $y$ in the first equation so that both equations $=y$ .

$2x+3y=1$

$3y=-2x+1$

$\frac{3y}{3}=\frac{-2x+1}{3}$

$y=-\frac{2}{3}x+\frac{1}{3}$

With this, we now know that both $-2-9$ and $-\frac{2}{3}x+\frac{1}{3}$ are equal to $y$ , so we can set them equal to each other.

$y=-\frac{2}{3}x+\frac{1}{3}$

$y=-11$

$-\frac{2}{3}x+\frac{1}{3}=-11$

Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for $x$ .

$-\frac{2}{3}x+\frac{1}{3}=-11$

$-\frac{2}{3}x=-11-\frac{1}{3}$

$-\frac{2}{3}x =-\frac{33}{3}-\frac{1}{3}$

$-\frac{2}{3}x =-\frac{34}{3}$

$-\frac{2}{3}x(-\frac{3}{2})=-\frac{34}{3}(-\frac{3}{2})$

$x=\frac{102}{6}=17$

$x=17$

Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.

4 0

2 years ago

Which number is greatest? 2.89 times 10 Superscript negative 8 1.997 times 10 Superscript 2 8.9 times 10 Superscript negative 6

love history [14]