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Alika [10]
3 years ago
14

Please solve y=x^2-6x-5 by factoring and by using the quadratic formula with work attached

Mathematics
1 answer:
Lynna [10]3 years ago
3 0

<u>Factoring:</u>

This equation cannot be factored because its roots are irrational (as shown by solving with the quadratic formula).  Also, to factor a quadratic equation, you need to find a pair of numbers whose product is equal to the c term (-5) and whose sum is equal to the b term (-6).  There is no pair of numbers which satisfies this, further showing that the equation cannot be factored.


<u>Quadratic Formula:</u>

The quadratic formula is x=\frac{-b ± \sqrt{b^{2}-4ac } }{2a}.

First, you need to find the a, b and c terms of your equation.  They are 1, -6, and -5 respectively.

Now, you must plug in to the equation and solve for x.  You must do so twice, once with a plus sign in the numerator and once with a minus.

\frac{6 ± \sqrt{(-6)^{2}-4(1)(-5) } }{2(1)} \\\frac{6 ± \sqrt{36+20} }{2} \\\frac{6 ± \sqrt{56} }{2} \\\ \frac{6 ± 2\sqrt{14} }{2} \\3+\sqrt{14} \\3-\sqrt{14}


The answers are 3+√14 and 3-√14.


Hope this helps!!


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Step-by-step explanation:

(5x-40)+7 = 2

5x-33 = 2

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A young female lion was brought into the wildlife zoo weighing 53.5 pounds. After two years, she weighed 5.5 times
Lera25 [3.4K]

Answer:

324

Step-by-step explanation:

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18(x + 1) = -54 pls help solve this...​
serg [7]

Answer:

x = 71

Step-by-step explanation:

18(x + 1) = -54

to start off, subtract 18 from both sides

18 - 18(x + 1) = -54 - 18

that should give you

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(its safe to take out paranthesis from problem by now) now take away 1 from each side

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7 0
3 years ago
The difference of two trinomials is x2 - 10x + 2. If one of the trinomials is 3x? - 11x - 4, then which expression could be the
klio [65]

Answer:

2x^2-x-6

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4x^2-21x-2

Step-by-step explanation:

The difference of two trinomials P(x) and Q(x) is x^2 - 10x + 2. This means that

P(x)-Q(x)=x^2-10x+2

or

Q(x)-P(x)=x^2-10x+2

If one of the trinomials is P(x)=3x^2-11x - 4, then

(3x^2-11x-4)-Q(x)=x^2-10x+2

or

Q(x)-(3x^2-11x-4)=x^2-10x+2

1. If (3x^2-11x-4)-Q(x)=x^2-10x+2, then

Q(x)=(3x^2-11x-4)-(x^2-10x+2)\\ \\Q(x)=(3x^2-x^2)+(-11x+10x)+(-4-2)\\ \\Q(x)=2x^2-x-6

2. If Q(x)-(3x^2-11x-4)=x^2-10x+2, then

Q(x)=(x^2-10x+2)+(3x^2-11x-4)\\ \\Q(x)=(x^2+3x^2)+(-10x-11x)+(2-4)\\ \\Q(x)=4x^2-21x-2

4 0
3 years ago
11 points
anyanavicka [17]

Answer:

9.100

9.10,00

1. 1,098,000

1.109,800,000

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