We will solve using the law of sines as follows:
Now, we solve for X:
So, the length of X is sqrt(3).
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Answer:
The answer can be calculated by doing the following steps;
Step-by-step explanation:
Answer:
we need to prove : for every integer n>1, the number is a multiple of 5.
1) check divisibility for n=1, (divisible)
2) Assume that is divisible by 5,
3) Induction,
Now,
Take out the common factor,
(divisible by 5)
add both the sides by f(k)
We have proved that difference between and
is divisible by 5.
so, our assumption in step 2 is correct.
Since is divisible by 5, then
must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.
Therefore, for every integer n>1, the number is a multiple of 5.
1) Let's write out both expressions subtracting 4m²+2mn+8n² from 2m²+6mn+2n²
2) Note that when we subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 we need to swap the sign by placing -1 outside the parentheses and then combine like terms adding those terms algebraically.