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3 years ago

Need help with this thanks

Mathematics

1 answer:

sladkih [1.3K]3 years ago

8 0

Answer:

C. 46.2

Step-by-step explanation:

$f(x) = 3x$

$f(15.4) = 15.4 \times 3 = 46.2$

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astra-53 [7]

Answer:

Darci fly the about 4 meters of string, but she didn't know there was a strong wind, after few minutes her kite was too far and the wind is about 200kph and her kite is getting crazy suddenly her string snaps and she can't find it anymore suddenly the wind was gone and Darci had a bad day.

4 0

3 years ago

Hi!! ;; please help :) 20 points! no links or websites. please .

Zolol [24]

Answer: 22

Step-by-step explanation:

(1 × 3) + [2 × 3 $\frac{1}{2}$ ] + [1 × 3 $\frac{3}{4}$ [1 × 4 $\frac{1}{4}$ ] + [3 × $\frac{3}{4}$ ] + [3 × 5 $\frac{1}{4}$ ]

= 3 + [2 × $\frac{3}{2}$ ] + [1 × $\frac{9}{4}$ ] + [1 × $\frac{4}{4}$ ] + [3 × $\frac{12}{4}$ ] + [3 × $\frac{5}{4}$ ]

= 3 + $\frac{6}{2}$ + $\frac{9}{4}$ + $\frac{4}{4}$ (equal to 1) + $\frac{36}{4}$ + $\frac{15}{4}$

= 3 + 3 + $\frac{9}{4}$ + 1 + 9 + $\frac{15}{4}$

= 16 + $\frac{9+15}{4}$

= 16 + $\frac{24}{4}$

= 16 + 6

= 22

3 0

3 years ago

Find an equation of the line. Write the equation using function notation.

vredina [299]

Answer:

f(x) = -5x +48

Step-by-step explanation:

A fairly easy way to write the equation of the perpendicular line is to swap the x- and y-coefficients, negating one of them. Then choose the constant in the equation to make it true at the given point.

<h3>Swapped coefficients</h3>

In this instance, we find it convenient to leave the coefficient of y as positive.

5y = x -10 . . . . . . original equation

y = -5x +c . . . . . . with coefficients swapped, x-coefficient negated

<h3>New constant</h3>

At the given point, the equation becomes ...

8 = -5(8) +c

48 = c . . . . . . . add 40

<h3>Equation of the perpendicular line</h3>

The equation of the line is then ...

y = -5x +48

f(x) = -5x +48 . . . . . . in functional notation

4 0

2 years ago

Help with the linear equations

IgorC [24]

Answer:

$y \: intercept = - 1 \frac{1}{2}$

Step-by-step explanation:

The y intercept form for the equation of a line is

$y = mx + c$

You should note that <em>c</em> represents the y-intercept of the line (where the line touches the y-axis)

$y = mx + c \\ \\ we \:were\: given \:the \:equation \:y = x - \frac{3}{2} \\ \\ therefore \: the\: value \:of \:c \:is\: - \frac{3}{2} \:or -1 \frac {1}{2}$

7 0

2 years ago

Can a function be concave down and positive everywhere?

aivan3 [116]

<span>Can a function be concave down and positive everywhere?
can be a semicircle
example, y=4+ $\sqrt{4-x^2}$
attachment 1

Can a function be increasing and be concave down everywhere?
no, concave down means increase slope then decrease slope

Can a function have two local extrema and three inflection points?
inflection points are where the concavity changes
it can be at the ends, the middle and the other end
like in atachment 2, the circles are inflection points

Can a function have 4 zeros and two local extrema?
no, as you can see in attachment 3, there can be 3 zeroes at most for 2 local extrema
</span>

8 0

3 years ago