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mote1985 [20]
3 years ago
5

Help plz. I hope you can tell with the picture says because I’m looking at it right now and I definitely can.

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
8 0

Answer:

Step-by-step explanation:

x= (-2 -1)h

x= (-2-1)4= -12

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0.5x -2 = 1.5x + 0.15
frutty [35]

Answer: x=−2.15

Step-by-step explanation : Alright Let's solve your equation step-by-step.

0.5x−2=1.5x+0.15

Step 1: Subtract 1.5x from both sides.

0.5x−2−1.5x=1.5x+0.15−1.5x

−x−2=0.15

Step 2: Add 2 to both sides.

−x−2+2=0.15+2

−x=2.15

Step 3: Divide both sides by -1.

−x

−1

=

2.15

−1

x=−2.15<em>        hope this helped!- Alex</em><u> </u>

8 0
3 years ago
F(x)= -2x^2<br>what is the vertex of this and/or how do you find the vertex??​
Doss [256]

Answer:

(0,0)

Step-by-step explanation:

x value of vertex = -b/2a

ax^2+bx+c

-2x^2+0x+0 sinc you have no value of b & c in your quadratic function

-b = 0

2a = (2)(-2)

-b/2a = (0/-4) = 0

x value of the vertex = 0

plug 0 in for all values of x in the function to find y coordinate value

-2(0)^2 = 0

(x,y) = (0,0)

7 0
2 years ago
HELP ME PLS I NEED THIS !!!!
ZanzabumX [31]

Answer:

Go google the answer

Step-by-step explanation:

3 0
3 years ago
19 dollars for 5 books
viktelen [127]

Answer:

$3.80 per book

Step-by-step explanation:

I divided 19 by 5 to get the price per book

3 0
3 years ago
PLEASE HELP HYPERBOLAS What is the length of the transverse axis ?<br> (x-1)^2/25-(y+3)^2/9=1
Sav [38]

Given equation of hyperbola is

\frac{(x-1)^{2}}{25}-\frac{(y+3)^{2}}{9}=1

Given hyperbola is the horizontal hyperbola

The standard form of the horizontal hyperbola is

\frac{(x-h)^{2}}{a^{2}}-\frac{(y-k)^{2}}{b^{2}}=1

When we compare these two equations, we get

h = 1, a = 5 , k = -3 and b = 3

Length of the transverse axis = 2a

Plug in the value of 'a' as 5

So,Length of the transverse axis = 2(5) = 10

7 0
3 years ago
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