Question

Determine the solution set of (x + 2)2 = 36. {6, -8} {4, -8} {4, -6}

Answer 1

(x + 2)^2 = 36
x^2 +4x + 4 = 36
x^2 +4x - 32 = 0
(x + 8)(x - 4)= 0

x+8 = 0
x = -8

x-4=0
x = 4

answer is {4, -8} (second choice)

Answer 2

Answer:

(B)(4,-8)

Step-by-step explanation:

The given equation is:

$(x+2)^2=36$

Solving the above equation, we get

⇒$x^2+4+4x=36$

⇒$x^2+4x+4-36=0$

⇒$x^2+8x-4x-32=0$

⇒$x(x+8)-4(x+8)=0$

⇒$(x-4)(x+8)=0$

Thus, the solution is x=-8 and x=4.

Therefore, the solution set is (4,-8) and Option B is correct.