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amm1812
3 years ago
14

The law of superposition is most relevant when studying which type of rock?

Geography
2 answers:
Stels [109]3 years ago
5 0

THE ANSWER IS

;sedimentary

Alja [10]3 years ago
3 0
~Hello there! ^_^

Your question: The Law of Superposition is most relevant when studying which type of rock..?

Your answer:The Law of Superposition is most relevant when studying about sedimentary rocks.

Happy Studying! =)

 


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i'm pretty sure it's giant

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The contour interval of a topographic map is 50 feet. How many contour lines would be drawn between sea level and an elevation o
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If the contour interval of a topographic map is 50 feet, THREE contour lines would be drawn between sea level and an elevation of 175 feet.

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19. The Hertzsprung-Russell diagram shown is divided into four sections.
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The section of the  Hertzsprung-Russell diagram that has the coolest and the brightest stars are the super-giants.

<h3>What is the  Hertzsprung-Russell diagram?</h3>

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brainly.com/question/22641110

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The lowest elevation found on earths land masses is located near which body of water?
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8 0
3 years ago
Suppose 0 is an angle in the standard position whose terminal side is in Quadrant IV and cot0= -6/7 Find the exact values of the
Sergio039 [100]
<h2>\sin \theta=\dfrac{p}{h} =\dfrac{-7}{\sqrt{85} }, \cos \theta=\dfrac{b}{h} =\dfrac{6}{\sqrt{85}}, \tan \theta=\dfrac{p}{b} =\dfrac{-7}{6},</h2><h2>\sec \theta=\dfrac{h}{b} =\dfrac{\sqrt{85} }{6} and \csc \theta=\dfrac{h}{p} =\dfrac{-\sqrt{85}}{ 7}</h2>

Explanation:

Given,

\cot \theta= \dfrac{-6}{7}

To find, the exact values of the five remaining trigonometric functions of \theta = ?

We know that,

\cot \theta= \dfrac{-6}{7}=\dfrac{b}{p}

Where, b = base and p = perpendicular

By Pythagoras's theorem,

Hypotaneous, h=\sqrt{p^2+b^2}

=\sqrt{(-6)^2+7^2}=\sqrt{36+49} =\sqrt{85}

In IVth quadrant,

\cot \theta and \sec \theta are positive.

\sin \theta=\dfrac{p}{h} =\dfrac{-7}{\sqrt{85} }, \cos \theta=\dfrac{b}{h} =\dfrac{6}{\sqrt{85}}, \tan \theta=\dfrac{p}{b} =\dfrac{-7}{6},

\sec \theta=\dfrac{h}{b} =\dfrac{\sqrt{85} }{6} and \csc \theta=\dfrac{h}{p} =\dfrac{-\sqrt{85}}{ 7}

7 0
3 years ago
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