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Mumz [18]
3 years ago
10

What is 3.106 x 10 in the 6th power written in standard form

Mathematics
1 answer:
Nitella [24]3 years ago
7 0
Think about moving the decimal to the right 6 times. so I believe your answer is 3106000.
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help me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me me
Trava [24]

Volume of the 3d composite figure is,

(7×6×5)+(7×6×5)/3

= 210+70

= 280 cm³

Relationship between the two volumes,

Volume of the rectangular prism is 3 times the volume of the pyramid.

Answered by GAUTHMATH

3 0
2 years ago
The blank of a number says how many times to use that number ia a multiplication
Evgesh-ka [11]
I'm pretty sure the answer is exponent since it tells you how many times to multiply the number beside it by itself.

Example:

{3}^{4}
It is NOT 3 × 4 = 12

It is 3 × 3 × 3 × 3 = 9 × 3 × 3 = 9 × 9 = 81

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
4 0
2 years ago
what is the probability that s+d>3 and s.d>3? write your answer as a decimal rounded to hundreth place
maw [93]

The probability that s+d > 3 and sd > 3 is 0.03.

<h3>Solution</h3>

Plot the inequalities

The region -5 ≤ s,d ≤ 5 is the square shaded in grey.

The region s + d > 3 is the region Q shaded to the right of the straight line.

The region sd > 3 is the region R shaded to the right of the curve d = 3/s.

Find the intersection of the three regions

From the figure, the region satisfying all the above three inequalities is the region to the left of the curve d = 3/s, bounded by the square region, i.e. the region R.

Probability of region R

The required probability is the Geometric probability of the intersection region R. It is calculated as

P(R) = ar(region R) / ar(square region P).

Calculate the areas of the regions

ar(region R) = area of the rectangle to the right in the first quadrant formed by dropping a vertical from point F - area under the curve d = 3/s in the first quadrant

\[\Rightarrow \;\; \mathrm{ar(\mathbf{R}) =} \int_{3/5}^5\frac{3}{s}ds = 25-3-3\ln\frac{25}{3} = 15.64.\]

ar(region P) = 25 × 25 = 625.

Calculate P(R)

The probability of the region R, P(R) = 15.64 / 625 = 0.025.

Rounding it to the hundredth place of decimal, P(R) = 0.03.

The probability that s+d >3 and sd>3, where -5 < s,d < 5, is 0.03.

Learn more about the Probability here

brainly.com/question/13604758


Disclaimer: The question was incomplete. Please find the full content below.

<h3>Question</h3>

What is the probability that s + d > 3 and sd > 3, where -5 ≤ s,d ≤5? Write your answer as a decimal rounded to the hundredth place.

#SPJ10

8 0
2 years ago
Which statement is true about the right angles ABC and DEF
cluponka [151]
The answer is the first one
7 0
3 years ago
Help me find this please ASAP.........................
Likurg_2 [28]
Third one down



------------------
5 0
3 years ago
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