Answer:
height of the cone = 4.01273885 units
Step-by-step explanation:
Volume of a cone(V) is given by:
....[1]
where,
r is the radius and h is the height of the cone.
As per the statement:
A cone with radius 5 units and ts volume is 105 cubic units
⇒r = 5 units and V = 105 cubic units
Substitute these given values and use
in [1] we have;

Multiply both sides by 3 we have;
⇒
Divide both sides by 78.5 we have;

or
h = 4.01273885 units
Therefore, the height of the cone is, 4.01273885 units
Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
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The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
(0,1) is the y intercept because the point (0,1) lies on the y axis.