All categories

3 years ago

Which bonds are broken by the strong acid step?

Chemistry

1 answer:

Anit [1.1K]3 years ago

8 0

Answer:

Covalent bonds between sugar and phosphate groups in upright of DNA double strand.

Explanation:

In DNA covalent bonds of sugar and phosphate are strong bonds which can be broken by acid step. These bond are strong covalent bonds which consists of carbon atoms combined with molecule of atom. In sugar the carbon atom cannot gain or loose electron. The bond formed by carbon atom is covalent bond only.

You might be interested in

A solution is made from ethanol, C2H5OH and water is 0.75 m. How many grams of ethanol are contained per 250. g of water?

kumpel [21]

Answer:

$m_{solute}=8.6g$

Explanation:

Hello,

In this case, the unit of concentration is molality which is defined by:

$m=\frac{n_{solute}}{m_{solvent}}$

Whereas the mass of the solvent is measured in kilograms. In such a way, with the given data, we first compute the kilograms of water:

$m_{solvent}=250g*\frac{1kg}{1000g} =0.25kg$

Then, we solve for the moles of the solute:

$n_{solute}=0.75\frac{mol}{kg}*0.25kg =0.19mol$

Finally since the molar mass of ethanol is 46 g/mol, we compute the grams for the given solution:

$m_{solute}=0.19*\frac{46g}{1mol} \\\\m_{solute}=8.6g$

Best regards.

8 0

3 years ago

What element has an electron configuration that ends in 2s2 2p4?

NISA [10]

Oxygen is the element. It has a total of 6 valence electrons.

5 0

4 years ago

In which of the titrations described below will the first (or only) equivalence point be reached upon the addition of 25.0 mL of

Mnenie [13.5K]

Answer:

1, 3, and 4

Step-by-step explanation:

We must calculate the volume of NaOH needed for each titration.

1) HCl

HCl + NaOH ⟶ NaCl + H₂O

n(HCl) = 25.0 mL × (0.100 mmol/1mL) = 2.50 mmol

n(NaOH) = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

2) H₂C₂O₄

H₂C₂O₄ + NaOH ⟶ NaHC₂O₄

n(H₂C₂O₄) = 50.0 mL × (0.100 mmol/1mL) = 5.00 mmol

n(NaOH) = 5.00 mmol H₂C₂O₄ × (1 mmol NaOH/1 mmol H₂C₂O₄)

= 5.00 mmol NaOH

V(NaOH) = 5.00 mmol × (1 mL/0.100 mmol) = 50.0 mL

3) HC₂H₃O₂

HC₂H₃O₂ + NaOH ⟶ NaC₂H₃O₂ + H₂O

n(HC₂H₃O₂) = 25.0 mL × (0.100 mmol/1mL) = 2.50 mmol

n(NaOH) = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl)

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

4) HBr

HBr + NaOH ⟶ NaBr + H₂O

n(HBr) = 25.0 mL × (0.100 mmol/1mL) =2.50 mmol

n(NaOH) = 2.50 mmol HCl × (1 mmol NaOH/1 mmol HCl)

= 2.50 mmol NaOH

V(NaOH) = 2.50 mmol × (1 mL/0.100 mmol) = 25.0 mL

Titrations 1, 3, and 4 reach the first or only equivalence point at 25.0 mL NaOH.

8 0

3 years ago

Read 2 more answers

Hydrazine reacts with oxygen according to the following equation: N2H4(g) +O2(g) → N2(g) + 2 H2O(l) How many L of N2, measured a

mihalych1998 [28]

Answer:

V ≈ 646.50 L

General Formulas and Concepts:

Chemistry - Gas Laws

Reading a Periodic Table
Stoichiometry
Combined Gas Law: PV = nRT
R constant - 62.4 (L · torr)/(mol · K)
Kelvin Conversion: K = °C + 273.15

Explanation:

Step 1: Define

RxN: N₂H₄ (g) + O₂ (g) → N₂ (g) + 2H₂O (l)

Given: 34.9 °C, 755.08 torr, 914.894 g H₂O

Step 2: Identify Conversions

Kelvin Conversion

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

Stoichiometry: $914.894 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} )(\frac{1 \ mol \ N_2}{2 \ mol \ H_2O} )$ = 25.3955 mol N₂

Temperature: 34.9 + 273.15 = 308.05 K

Step 4: Find Volume

Substitute variables: (755.08 torr)V = (25.3955 mol)(62.4 (L · torr)/(mol · K))(308.05 K)
Multiply: (755.08 torr)V = 488160 L · torr
Isolate V: V = 646.502 L

Step 5: Check

We are given 5 sig figs as our lowest. Follow sig fig rules and round.

646.502 L ≈ 646.50 L

6 0

3 years ago

As ice melts from a solid to a liquid, A) entropy increase

Dovator [93]

That answer is false

4 0

3 years ago