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Igoryamba
3 years ago
7

kody spent $20.00 during his last outing at the bowling alley this included a one time shoe rental fee of $3.50 he spent the res

t of the money on bowling a number of games. If it took Kody 45 minutes to bowl each game and he spent 2 hours and 15 minutes bowling how much did it cost per game ?
Mathematics
1 answer:
fredd [130]3 years ago
6 0

Answer: Kody spent $5.50 per game

Step-by-step explanation:

First, I subtracted the $3.50 from $20.00. Then I was left with $16.50. Then I added 45 3 times and got 135 which is equal to 2 hours and 15 minutes. So then I did $16.50 divided by 3 and got $5.50 per game.

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3 years ago
factor completely 4x5 − 20x4 − 36x3. 4(x5 − 5x4 − 9x3) x3(4x2 − 20x − 36) x2 − 5x − 9 4x3(x2 − 5x − 9)
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3 0
3 years ago
Read 2 more answers
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Neko [114]

Answer:

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Step-by-step explanation:

We are given that x bar = 60​, s = 12​, n = 30​, and alpha = 0.10

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Alternate Hypothesis, H_1 : \mu \neq 50

The test statistics we will use here is;

                    T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~  t_n_-_1

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              n = sample size = 30

So, Test statistics = \frac{60-50}{\frac{12}{\sqrt{30} } } ~ t_2_9

                             = 4.564

At 10% significance level, t table gives critical value of 1.311 at 29 degree of freedom. Since our test statistics is more than the critical value as 4.564 > 1.311 so we have sufficient evidence to reject null hypothesis as our test statistics will fall in the rejection region.

P-value is given by, P(t_2_9 > 4.564) = less than 0.05% {using t table}

Here also, P-value is less than the significance level as 0.05% < 10% , so we will reject null hypothesis.

Therefore, we conclude that \mu\neq 50.

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3 years ago
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