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Arte-miy333 [17]
3 years ago
8

Pasha works as a food scientist. He designed a recipe for crackers that are 60% wheat flour by weight. He made a test batch of t

he crackers from 1 1/4 total pounds of ingredients. What weight of wheat flour did Pasha use in the test batch?
Mathematics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

the weight of wheat flour  Pasha used in the test batch is 3/4 pounds

Step-by-step explanation:

According to the given statement:

Pasha designed a recipe for crackers that are 60% wheat flour by weight

60% = 60/100 = 0.6 = 6/10

He made a test batch of the crackers from 1 1/4 total pounds of ingredients.

First of all change the whole fraction which is 1 1/4 into improper fraction.

1 1/4 = 5/4

Now multiply 6/10 with 5/4 to get the weight of wheat flour Pasha used in the test batch.

= 6/10 * 5/4

6 and 4 will be cancelled out by table of 2.

= 3/10 * 5/2

Now we can cancel out 5 and 10 by the table of 5.

3/2 * 1/2

Now multiply both the terms:

3/4 pounds

Thus the weight of wheat flour  Pasha used in the test batch is 3/4 pounds ....

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The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 6
Andre45 [30]

Answer:

the rate at which the height of the box is decreasing is -0.0593 cm/s

Step-by-step explanation:

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area of the base increases at a rate of 6 cm²/sec

so change in the area of the base with respect to time dA/dt = 6 cm²/sec

each side of the base is 15 cm long

so Area of the base = 15 cm × 15 cm = 225 cm²

the rate at which the height of the box is decreasing = ?

Now,

V = Ah

dv/dt = 0 ⇒ Adh/dt + hdA/DT = 0

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