All categories

3 years ago

Which property applies only to addition and subtraction

Mathematics

1 answer:

ad-work [718]3 years ago

3 0

Addition you add and in subtraction you subtract

You might be interested in

Which formula gives the area of a rectangle?

Tpy6a [65]

Answer:

$L*W=Area$

Step-by-step explanation:

The formula Length x Width = Area is the correct formula for the area of a rectangle. The same formula works for a square!

6 0

4 years ago

Read 2 more answers

What would the answer to the equation 3+6x=11-4y be

klemol [59]

   6x + 3 = -4y + 11
         - 3       - 3
         6x = -4y + 8
   6x + 4y = -4y + 4y + 8
   6x + 4y = 8
6x - 6x + 4y = -6x + 8
   4y = -6x + 8
      4    4
   y = -1¹/₂x + 2

6 0

3 years ago

A media company wants to track the results of its new marketing plan, so the video production manager recorded the number of vie

Alisiya [41]

Answer:

$f(x)=5120(1.25)^{x}$

Step-by-step explanation:

As per the given question

As we know that

f(x) and x are related by following equation

$f(x)=a( {b})^{x}$

where

b is the common ratio

Now first we have to compute the value for b which are as follows

$\frac{6400}{5120}= 1.25$

$\frac{8000}{6400}= 1.25$

Like if we take the ratio by this method than it comes 1.25

Therefore the common ratio, b = 1.25

So,

a = 5,120

Hence, the equation which model the relationship between the number of weeks and the number of viewers is

$f(x)=5120(1.25)^{x}$

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=

BARSIC [14]

<h3>Answer: -2</h3>

======================================================

Work Shown:

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\$

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\$

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

$\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\$

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\$

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0

3 years ago

Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar

Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

$((a, b), (c, d))\in R$