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TEA [102]
4 years ago
10

Write parametric equations of the line 2x-y=3

Mathematics
2 answers:
Kruka [31]4 years ago
5 0

Answer: The required parametric equation is y=2t-3.

Step-by-step explanation:

Since we have given that

2x+-y=3

We need to rewrite in parametric equation:

The parametric equation is written as

f(x)=y=at+b

So, Arranging the given equation in the above equation, we get

2x-y=3\\\\2x-3=y\\\\f(x)=y=2x-3

And then put x = t, to get the exact parametric form.

Hence, the required parametric equation is y=2t-3.

dangina [55]4 years ago
4 0
In this item we are given with the equation, 2x - y = 3. The equation contains two variables, x and y. We assume in this item that the value of x is independent of the value of y; however, y values depends on the given values of x. In parametric form, the equation would take the form,

    f(x) = y = ax + b

where a is the numerical coefficient of x and b is constant. Transforming the given equation to this form,

   f(x)  = y = 2x - 3
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there are two identical glasses. one glass is 5/6 full. the other is 3/4 full. water is poured from one glass to the other so th
goldenfox [79]

Answer:

1 7/12

Step-by-step explanation:

because the water was poured to the other glass so it means that we are adding

= 5/6 + 3/4

={(2×5) + (3×3)}/12

that 12 is due to LCM of 6 and 4

={ 10 + 9 }/12

= 19/12

= 1 7/12

those are my thoughts

5 0
4 years ago
Please help with this.
icang [17]

Answer:

g(1)=-72; g(n)=g(n-1)*(1/6)

Step-by-step explanation:

g(1)= -72*(1/6)^(1-1)=-72*(1/6)^0=-72*1=-72

g(2)=-72*(1/6)^(2-1)=-72*(1/6)^1=-72*(1/6)=-12

g(2)=g(1)*(1/6)

g(n)=g(n-1)*(1/6)

5 0
3 years ago
Read 2 more answers
6÷9384 steps into steps
Kitty [74]

Answer:

1564

Step-by-step explanation:

  1. 6/9384

1564

6/9384

-6

_____

33

-30

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38

- 36

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24

-24

__________

0

5 0
3 years ago
Easy question!(exponents) Plz help!
NeTakaya
X=-2/5

Steps:
6^x/3 +2 = 6^-14x/3
x/3+2 = -14x/3.
x +6 = -14x (multiply both sides by 3)
x = -14x - 6 (Substract 6 from both sides)
x + 14x = -6 (add 14x to both sides)
15x = -6 (collect like terms)
x = -2/5 (divide both sides by 15)

4 0
3 years ago
The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili
Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean of a population is 74 and the standard deviation is 15.

This means that \mu = 74, \sigma = 15

Question a:

Sample of 36 means that n = 36, s = \frac{15}{\sqrt{36}} = 2.5

This probability is 1 subtracted by the pvalue of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{78 - 74}{2.5}

Z = 1.6

Z = 1.6 has a pvalue of 0.9452

1 - 0.9452 = 0.0548

0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

Question b:

Sample of 150 means that n = 150, s = \frac{15}{\sqrt{150}} = 1.2247

This probability is the pvalue of Z when X = 77 subtracted by the pvalue of Z when X = 71. So

X = 77

Z = \frac{X - \mu}{s}

Z = \frac{77 - 74}{1.2274}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

X = 71

Z = \frac{X - \mu}{s}

Z = \frac{71 - 74}{1.2274}

Z = -2.45

Z = -2.45 has a pvalue of 0.0071

0.9929 - 0.0071 = 0.9858

0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c. A random sample of size 219 yielding a sample mean of less than 74.2

Sample size of 219 means that n = 219, s = \frac{15}{\sqrt{219}} = 1.0136

This probability is the pvalue of Z when X = 74.2. So

Z = \frac{X - \mu}{s}

Z = \frac{74.2 - 74}{1.0136}

Z = 0.2

Z = 0.2 has a pvalue of 0.5793

0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

5 0
3 years ago
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