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3 years ago

Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Mathematics

1 answer:

fiasKO [112]3 years ago

4 0

Answer:

B. x + 6

C. 4x - 1

Step-by-step explanation:

To get the two binomials of the trinomial, you split the middle term, like so:

$4x^2 - x + 24x - 6\\$

Group:

$(4x^2 - x) (24x - 6)$

Take out the GCF (Greatest Common Factor):

x(4x - 1) 6(4x - 1)

(x + 6) (4x - 1)

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A radio telescope has a parabolic surface, as shown below. If the telescope is 5 m deep and 40 m wide, how far is the focus from

Montano1993 [528]

Answer:

i think the answer is 8m

Step-by-step explanation:

4 0

3 years ago

20 POINTS - 1 EASY QUESTION

Vaselesa [24]

Answer and explanation:

Geometary software is merely a software implementation of solving the area of a triangle. Therefore geometry software employs all the methods used in coordinate algebra(manual) albeit behind the scenes, in the console of the software, and just displays the area in the screen after solving. While geometry software displays the area using automated methods in code, coordinate algebra solves area of the triangle manually using several steps. In both cases, we observe that algebra is required to solve area of the triangle as it is part of the algorithm used in the code for the geometry software. Also being able to use the geometry software requires that one understand coordinate algebra to be able to plot lines, points and planes at the correct locations on the screen and get desired result.

7 0

4 years ago

In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0

kolbaska11 [484]

Answer:

$Q_3 = 56.45$ --- The third quartile

$Var = 370.18$ -- Variance

Step-by-step explanation:

Given

$Q_1 = 30.8$ -- First quartile

$Q_2 = 48.5$ --- Median

$\bar x = 42$ --- Mean

$Skp = -0.38$ --- Coefficient of skewness

Solving (9): The third quartile $Q_3$

This is calculated from

$Skp = \frac{Q_1 + Q_3 - 2Q_2}{Q_3 - Q_1}$

So, we have:

$-0.38 = \frac{30.8 + Q_3- 2*48.5}{Q_3 - 30.8}$

Cross Multiply

$-0.38 (Q_3 - 30.8)= 30.8 + Q_3- 2*48.5$

Open bracket

$-0.38Q_3 + 11.704= 30.8 + Q_3- 97.0$

Collect like terms

$-0.38Q_3 -Q_3= 30.8 - 97.0- 11.704$

$-1.38Q_3= -77.904$

Divide both sides -1.38

$Q_3 = \frac{-77.904}{-1.38}$

$Q_3 = 56.45$ --- approximated

Solving (b): The variance

First, calculate the standard deviation from:

$3IQR = 4SD$

$IQR= Q_3 - Q_1$

So:

$3IQR = 4SD$

$3(Q_3 - Q_1) = 4SD$

Make SD the subject

$SD = \frac{3}{4}(Q_3 - Q_1)$

$SD = \frac{3}{4}(56.45 - 30.8)$

$SD = \frac{3}{4}*25.65$

$SD = \frac{3*25.65}{4}$

$SD = \frac{76.95}{4}$

$SD = 19.24$

So, the variance is:

$Var = SD^2$

$Var = 19.24^2$

$Var = 370.18$

5 0

3 years ago

To the nearest tenth how long is a craft box

hjlf

To the nearest tenth it’s a 20

4 0

3 years ago

Suppose that you and a friend are playing cards and you decide to make a friendly wager. The bet is that you will draw two cards

ehidna [41]

The amount of winning is more than amount of loosing. Then the amount of winning will be $3738.

<h3>How to find that a given condition can be modelled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials.

The expected value will be

E(X) = np

Suppose that you and a friend are playing cards, and you decide to make a friendly wager.

The bet is that you will draw two cards without replacement from a standard deck.

If both cards are spades, your friend will pay you $39.

Otherwise, you have to pay your friend $5.

If this same bet is made 623 times.

The maximum amount of winning will be

E(win) = np

We have

p = 0.25

n = 623

Then we have

E(win) = 0.25 × 623

E(win) = 155.75

Then the winning amount will be

WA = 155.75 × 39

WA = $6074.25

The maximum amount of loosing will be

E(loose) = np

We have

p = 0.75

n = 623

Then we have

E(loose) = 0.75 × 623

E(loose) = 467.25

Then the loosing amount will be

LA = 467.25 × 5

LA = $2336.25

Then the amount of winning will be

⇒ $ 6074.25 - $ 2336.25

⇒ $ 3738

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

3 0

2 years ago