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RoseWind [281]
4 years ago
7

Please solve this literal equation for the variable "f"

Mathematics
1 answer:
Tatiana [17]4 years ago
8 0
\frac{df+10}{6}= g

Now, multiply both sides by 6 and you get.....

 df+10=6g

now, subtract 10 on both sides and you get.....

df=6g-10

now divide both sides by d to get f by itself and you get........

f= \frac{6g-10}{d}

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Please find the perpendicular line slope equation please! Thanks!
lana66690 [7]

We need to convert this equation to slope-intercept form first.

We can do that by solving for y.

x - 5y = 15

<em><u>Add 5y to both sides.</u></em>

x = 5y + 15

<em><u>Subtract 15 from both sides.</u></em>

x - 15 = 5y

<em><u>Divide both sides by 5.</u></em>

y = 1/5x - 3

We now know the slope is 1/5.

The slope of the line perpendicular to the line with a slope of 1/5 is -5.

The slope of a perpendicular line is the negative reciprocal of the original slope.

Using a graphing calculator, we know the y-intercept of the line that is perpendicular to the original line must have a y-intercept of -6 to run through the points (-2, 5).

The equation of the new line is y = -5x - 6.


5 0
3 years ago
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What is the area of the shape below?
Sergeu [11.5K]
Answer:

Area = 886cm^2

Step-by-step explanation:

34 • 16 = 544

19 • 11 = 209

25 - 11 = 14

14 • 19 = 266/2

266/2 = 133

544 + 209 + 133 = 886cm^2
4 0
3 years ago
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Find the diameter of the circles having areas of 2464 cm square .​
Katena32 [7]

Answer:

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4 0
3 years ago
A + b = 10 <br> a - b = 2
____ [38]

Answer:

a = 6 , b = 4

Step-by-step explanation:

a + b = 10................equation 1

a - b = 2..................equation 2

Solving equation 1 and 2 we get

a + b = 10

<u>a - b =  2</u>

2a = 12

a = 12/2

Therefore a = 6

Now

putting a = 6 in equation 1

6 + b = 10

b = 10 - 6

Therefore b = 4

8 0
3 years ago
Let n be an odd integer with exactly 11 positive divisors. Find the number of positive divisors of 8n^3
Tom [10]

Answer: 124

Step-by-step explanation:

As we know, the total number of positive divisors of n is the product of one more than each exponent in the prime factorization of n.

We know this product is equal to 11.

Since 11 is prime, so there can be only one number in this product, so the prime factorization of n must be $n=p^{10}$, where p is a prime number.

We take a cube of the prime factorization of n to give us a prime factorization for n^3

$$n^{3}=\left(p^{10}\right)^{3}=p^{30} .$$

We see that n^{3}\text{ has }$30+1=31$ positive divisors.

Now, 8n^3=2^3\times p^{30}

Totald divisiors = (3+1)(30+1)=4\times31=124

Hence, the number of positive divisors of 8n^3=124

4 0
3 years ago
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