Question

. In this example, red flower coloring is dominant to white, and your population of 200 plants has 150 plants with red flowers. What are the allele frequencies and the genotype frequencies for this population, assuming Hardy-Weinberg equilibrium

Answer 1

Answer:

a) The allele frequencies are - $p= 0.8660\\q= 0.134$

b) Genotype frequencies for this population- $p^2=0.75, q^2= 0.0179, 2pq = 0.2321$

Explanation:

Given ,

Red color of flower is dominant to white color flower

Let "R" represents allele for red color and "r" represents allele for white color

out of $200$ flower, $150$ are red flowers.

So the frequency of red flowers with genotype "RR" is equal to

$p^{2} = \frac{150}{200} \\p^{2} =0.75$

As per hardy Weinberg's I equilibrium equation -

$p+q=1\\p=\sqrt{p^2} \\p=\sqrt{0.75} \\p= 0.8660\\q= 1-p\\q= 1-0.8660\\q = 0.134$

a) The allele frequencies are - $p= 0.8660\\q= 0.134$

Frequency of genotype "rr" i.e homozygous recessive white flower is

$q^{2} \\0.134^2\\q^2 = 0.0179$

Substituting the values of $p^2$ and $q^2$, in below equation, we get -

$p^2+2pq+q^2=1\\2pq= 1-p^2-q^2\\2pq= 1-0.75-0.0179\\2pq=0.2321$

b) Genotype frequencies for this population- $p^2=0.75, q^2= 0.0179, 2pq = 0.2321$