All categories

3 years ago

What is the noble gas notation for oxygen?

Chemistry

1 answer:

madreJ [45]3 years ago

8 0

Answer:

The noble gas notation of oxygen is $O^{2-}$ .

Explanation:

The atomic number of oxygen - 8

Chemical symbol of oxygenn -"O"

Electronic configuration - $1s^{2}2s^{2}2p^{4}$

The nearest noble gas is "Neon".

To get the nearest noble gas configuration oxygen requires two electrons.

Any element to gain electrons indicated by the negative charge.

Therefore, The noble gas notation of oxygen is $O^{2-}$ .

You might be interested in

One of the main ideas of the Quantum Theory is that:

gladu [14]

The energy of an electron can be change only by set amounts.

The electrons in an energy level of an atom can only move to a higher or lower energy level only if it absorbs or emits a certain amount of energy. If the electron does not have enough energy to move to the next energy level then it will never move.

8 0

3 years ago

Read 2 more answers

Calculate the amount of moles in 6.75 liters of nitrogen gas.

tia_tia [17]

Answer:

There are 0.301 moles of N2 gas in 6.75 liters of N2 gas.

Explanation:

Given,

Volume of N2 gas = 6.75 L

We know,

At STP,

Number of moles = $\frac{Volume}{22.4 L}$ [Here 22.4 liter is the molar volume of any gas at STP]

= $\frac{6.75L}{22.4L}$

= $0.301$

∴There are 0.301 moles of N2 gas in 6.75 liters of N2 gas.

7 0

3 years ago

What is the molecular formula for heptachlorine hexoxide

N76 [4]

Answer:

CI706

Explanation:

4 0

2 years ago

Read 2 more answers

A 1.50 liter flask at a temperature of 25°C contains a mixture of 0.158 moles of methane, 0.09 moles of ethane, and 0.044 moles

RUDIKE [14]

This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:

P = P1 + P2 + P3
P = (82.0575 atm.cm^3/mol.K)( 298.15 K)/1.50 x 10^3 cm^3) x (<span>0.158 mole + 0.09 mol + 0.044 mol) = 4.76 atm</span>

3 0

4 years ago

A chemist needs 10 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%,

mojhsa [17]

Answer:

a) 1 litre of 10% solution and 7 litre of 20% solution

b) 1.67 litres of 50% solution and 8.33 litres of the 20% solution

c) 3.75 litres of 50% solution and 6.25 litres of 20% solution

Explanation:

Given:

chemist needs = 10 liters of a 25% acid solution

Concentration of three solutions that are to be mixed = 10%, 20% and 50%.

Solution:

A) Use 2 liters of the 50% solution

Let us mix this with 10% and 20% solution

They will have to equal 8 litres

Let x=20% solution

Then (8-x) =10%

So the equation becomes,

10%(8-x)+ 20%x+50%(2)=25(10)

(0.1)(8-x) +0.2x+0.50(2)= 0.25(10)

0.8-0.1x+0.2x+1.0=2.5

0.2x-0.1x=2.5-0.8-1.0

0.1x=0.7

$x=\frac{0.7}{0.1}$

x= 7

so, 8-x = 8 -7= 1 litre of 10% solution and 7 litre of 20% solution

B)Use as little as possible of the 50% solution

Let x be the amount of 50% solution.

Then(10-x) be the 20% solution

Now the equation becomes,

50%(x)+20%(10-x)=25%(10)

0.50x+0.2(10-x)=0.25(10)

0.5x+2.0-0.2x=2.5

0.3x=2.5-2.0

0.3x=0.5

$x=\frac{0.5}{0.3}$

x=1.67

now (10-x)=(10-1.67)=8.33

so there will be 1.67 litres of 50% solution and 8.33 litres of the 20% solution

c) ) Use as much as possible of the 50% solution

Let x be the amount of 50% solution.

Then(10-x) be the 20% solution

Now the equation becomes,

50%(x)+10%(10-x)=25%(10)

0.50x+0.1(10-x)=0.25(10)

0.5x+1.0-0.1x=2.5

0.4x=2.5-1.0

0.4x=1.5

$x=\frac{1.5}{0.3}$

x=3.75

Now, (10-x)=(10- 3.75)=6.26

So there will be 3.75 litres of 50% solution and 6.25 litres of 20% solution

5 0

3 years ago