Answer:
1.4 * 10^-3
Explanation:
The equilibrium expression can be written as follows:
Keq = P [HD]^2/[ P[H2] * P[D2]]
Where P is pressure
1.80= (2.7 * 10^-3)^2 / ( 1.1 * 10^-3 * P[H2])
P[H2] = [2.7 * 10^-3]^2 / [1.8 * 1.1 * 10^-3]
P[H2] = 1.4 * 10^-3 atm
Solution
The mole is the number of particles contained in a substance
1 mol = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass
mol = mass : molar mass
mass = mol x molar mass
Molar mass = 58,6934 g/mol
Input the value :
mass = 0.0321 x 58,6934 g/mol
mass = 1.884 g
Hey there!:
1 mole O2 ----------------- 22.4 L ( at STP )
( moles O2 ) -------------- 2.50 L
moles O2 = 2.50 * 1 / 22.4
moles O2 = 2.50 / 22.4
moles O2 = 1.12*10⁻¹
Answer B
Hope that helps!
The answer is the el second one since it is a physical change
