Given the expression,

We will have to rationalize the denominator first. To rationalize the denominator we have to multiply the numerator and denominator both by the square root part of the denominator.
![[(8x-56x^2)(\sqrt{14x-2})]/[(\sqrt{14x-2})(\sqrt{14x-2})]](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B%28%5Csqrt%7B14x-2%7D%29%28%5Csqrt%7B14x-2%7D%29%5D%20)
If we have
, we will get
by multiplying them. And
.
So here in the problem, we will get,
![[(8x-56x^2)(\sqrt{14x-2})]/(14x-2)](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%2814x-2%29%20)
Now in the numerator we have
. We can check 8x is common there. we will take out -8x from it, we will get,


And in the denominator we have
. We can check 2 is common there. If we take out 2 from it we will get,

So we can write the expression as
![[(-8x)(7x-1)(\sqrt{14x-2})]/[2(7x-1)]](https://tex.z-dn.net/?f=%20%5B%28-8x%29%287x-1%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B2%287x-1%29%5D%20)
is common to the numerator and denominator both, if we cancel it we will get,

We can divide -8 by the denominator, as -8 os divisible by 2. By dividing them we will get,


So we have got the required answer here.
The correct option is the last one.
Could you please explain how to work this app
Answer:
the probability that there will be a seat available for every passenger who shows up is 0.74
Step-by-step explanation:
if the probability of choosing a passenger that will not show up is 5% , then the probability of choosing a passenger that will show up is 95%.
Denoting event X= x passengers will show up from the total of 52 that purchased the ticket
Then P(X) follows a binomial probability distribution, since each passenger is independent from others. Thus
P(X) = n!/((n-x)!*x!)*p^x*(1-p)^(n-x)
where
n= total number of passengers hat purchased the ticket= 52
p= probability of choosing a passenger that will show up
x = number of passengers that will show up
therefore the probability that the number does not exceed the limit of 50 passengers is:
P(X≤50)= ∑P(X=i) from i=0 to i=50 =F(50)
where F(x) is the cumulative binomial probability distribution, then from tables:
P(X≤50)= F(50) = 0.74
therefore the probability that there will be a seat available for every passenger who shows up is 0.74
Answer:
-8.8
Step-by-step explanation:
We begin by simplifying the parenthesis through multiplication. Parenthesis is a structure which signals multiplication happening.

We now begin combining like terms across the equal sign by performing the inverse or doing the opposite. Move first the 8.11 by subtracting it from both sides.

Now, move 4.3v across by subtracting it from both sides.


Finally, we divide both sides by the coefficient of v.
