The equation may also have one common root or no real roots. This gives the maximum number of points where the parabola<span> intersect as </span>2<span>. ... When that is the case, the twp </span>parabolas<span> intersect at 4 </span>distinct<span> points. The maximum number of points of intersection of </span>two distinct parabolas<span> is 4.</span>
Answer:
20 in²
Step-by-step explanation:
Assuming that the width of the sign is x, then from the question, we're told that the length is 5 times it's width, so
b = x inches
l = 5x inches
Again, we're told that the perimeter of the sign is 24 inches, and we know already that the perimeter of a rectangle is given as
Perimeter = 2(l + b), substituting this, we have
24 = 2(5x + x)
24 = 10x + 2x
24 = 12x
x = 24 / 12
x = 2 inches.
Since x is the width of the rectangle, and it's 2 inches, we use it to find the length of the sign.
l = 5 * 2
l = 10 inches.
Then, we are asked to find the area of the sign. Area of a rectangle is given as
A = l * b, so if we substitute, we have
Area = 10 * 2
Area = 20 square inches
Answer:
a)2975
b)3450
Step-by-step explanation:
I would have to say 32,4 but i would double check it