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nordsb [41]
4 years ago
5

Two consecutive integers add to 51. what are the integers?

Mathematics
2 answers:
Nataly [62]4 years ago
7 0
25 and 26...........
Vedmedyk [2.9K]4 years ago
4 0

Answer: 25 and 26

Step-by-step explanation: This problem states that the sum of two consecutive integers is 51 and it asks us to find the integers. Two consecutive integers can be represented as followed.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer </em>

Since the sum of our two con consecutive integers is 51, we can set up an equation to represent this.

X + X + 1 = 51

Now, we can simplify on the left side of our equation.

2x + 1 = 51

      -1    -1   ← subtract 1 on both sides

2x = 50

÷2    ÷2   ← divide both sides by 2

X = 25

X + 1 = 26

Therefore, our two consecutive integers are 25 and 26.

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37th term; a1 = 2.3; d = -2.3
Sindrei [870]

<u>Answer:</u>

37th term of given arithmetic sequence a_1 = 2.3; d = -2.3 is -80.5.

<u>Solution:</u>

Given that  

Need to determine 37th term, when a_1 = 2.3, d = -2.3

Means first term of arithmetic sequence = a_1 = 2.3 and common difference d = -2.3

<u><em>Formula for nth term of arithmetic sequence is  </em></u>

\mathrm{a}_{\mathrm{n}}=\mathrm{a}_{1}+(\mathrm{n}-1) \mathrm{d}  --- equation 1

\text { In our case } a_{1}=2.3, d=-2.3

We need to determine 37th term so n = 37.

On substituting given values in equation (1) we get

\mathrm{a}_{37}=\mathrm{a}_{1}+(37-1) \mathrm{d}

\begin{array}{l}{\Rightarrow a_{37}=2.3+(37-1)(-2.3)} \\\\ {\Rightarrow a_{37}=2.3(1-36)=2.3 \times 35=-80.5}\end{array}

Hence 37th term of given arithmetic sequence is -80.5

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