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nordsb [41]
3 years ago
5

Two consecutive integers add to 51. what are the integers?

Mathematics
2 answers:
Nataly [62]3 years ago
7 0
25 and 26...........
Vedmedyk [2.9K]3 years ago
4 0

Answer: 25 and 26

Step-by-step explanation: This problem states that the sum of two consecutive integers is 51 and it asks us to find the integers. Two consecutive integers can be represented as followed.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer </em>

Since the sum of our two con consecutive integers is 51, we can set up an equation to represent this.

X + X + 1 = 51

Now, we can simplify on the left side of our equation.

2x + 1 = 51

      -1    -1   ← subtract 1 on both sides

2x = 50

÷2    ÷2   ← divide both sides by 2

X = 25

X + 1 = 26

Therefore, our two consecutive integers are 25 and 26.

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Answer:

$3098.93

Step-by-step explanation:

We can use the formula for compound growth to solve this. The formula is:

F=P(1+r)^t

Where

F is the future value (the value at end of 14 years, our answer)

P is the initial amount invested ($1250)

r is the interest rate, in decimal (6.7% is 0.067)

t is the time in years (14, in our case)

<em>Plugging in all the information</em> we have:

F=P(1+r)^t\\F=1250(1+0.067)^14\\F=1250(1.067)^14\\F=3098.93

The account will accrue $3098.93 after 14 years.

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3 years ago
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A television​ network, Network​ A, is scheduling its fall lineup of shows. For the Tuesday night 8 p.m.​ slot, Network A has sel
Mazyrski [523]

Answer:

The number of viewers Network A expects will watch their show is 1.4 million viewers.

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The expected value is calculated by multiplying the possible outcomes by the probability of their occurrence and adding the results

Therefore, we have the expected value given by the following expression;

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Estimated network A viewers where network B schedule a different show = 1.6 million viewers

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Expected value, E of Network A viewers is therefore;

E = 1.1 × 0.4 + 1.6 × 0.6 =  0.44 + 0.96 = 1.4 million viewers.

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