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3 years ago

When x=8 and y=20 find y when x=42

Mathematics

1 answer:

ella [17]3 years ago

7 0

When x=42 that means it is 8x6 so that means that the y = 120 becuase its 20x6
answer= y=120

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a bowl contains 4 peaches and 4 apricots. Maine randomly selects one, puts it back, and randomly selects another. what is the pr

almond37 [142]

1/4 or 25% because...

The probability that Maine picks an apricot is 4/8

The probability that Maine picks an apricot after putting the first apricot back is still 4/8

4/8 x 4/8 = 16/64 = 1/4

4 0

3 years ago

What is the best approximation of the solution to the

denis-greek [22]

Answer: Choice C. (1, -6)

Explanation: The two lines cross at around this location. The solution point is on both lines at the same time.

3 0

3 years ago

Please help.<br> Its a True or False question.

faust18 [17]

Answer:

1. False

2. True

3. True

Step-by-step explanation:

Remark

The point of this question is to encourage you to make use of your calculator. Every calculator can find square roots as far as I know.

Givens

$\sqrt{70}$ = 8.367

$\sqrt{72}$ = 8.49

$\sqrt{77}$ = 8.77

One

Point A is roughly 8.15. The square root of 70 is over 8.3 So square root 70 is to the right of point A. False.

Two

Square root 72 is 8.49. B is 8.3 and C is 8.6. The statement is True

Three

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4 0

3 years ago

Read 2 more answers

CHALLENGE PROBLEM Danny's Department Store advertises savings of

Oksanka [162]

Discount are used to reduce the costs of items

The percent paid to determine the advertisement is incorrect

<h3>How to determine the correct percentage</h3>

The initial prices are given as: $44.00 to $152.00

And the discount is: 45% to 51%

At a discount of 45%, the price of the items would be:

$Price = \$44.00 * (1 - 45\%)$

$Price = \$24.2$

$Price_2 = \$152.00 * (1 - 45\%)$

$Price_2 = \$83.6$

At a discount of 51%, the price of the items would be:

$Price = \$44.00 * (1 - 51\%)$

$Price = \$21.56$

$Price_2 = \$152.00 * (1 - 51\%)$

$Price_2 = \$74.48$

The calculates prices show that the percent paid to determine the advertisement is incorrect