The quotient of 6x^3+2x^2−x and x is 6x^3+2x^2−x divided by x
The value of the quotient 6x^3+2x^2−x by x is 6x^2 + 2x - 1
<h3>How to determine the quotient</h3>
The quotient expression is given as:
6x^3+2x^2−x divide by x
The above means that,
We divide 6x^2 by x, we divide 2x^2 by x and we divide -x by x.
So, we have:
6x^3+2x^2−x divide by x = 6x^2 + 2x - 1
Hence, the value of the quotient 6x^3+2x^2−x is 6x^2 + 2x - 1
Read more about quotient at:
brainly.com/question/7068223
It would take 60 days to add 30 million new accounts
1.3/4 of right angle is 3/4*90=67.5
2.5/4 of right angle is 5/4*90=112.5
3.5/3 of right angle is 5/3*90=150
4.2/3 of right angle is 2/3*90=60
Answer:
x = 15
5x + 55 = 2x +100, plug in 15 and they are equal
Answer:
B
Step-by-step explanation: