<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer:
The answer is 24 yards.
Step-by-step explanation:
a² + b² = c²
10² + b² = 26²
100 + b = 676
676 - 100 = 576
√576 = 24 yards
14x45=630
43×2=86
(14×45)-(43×2)= 630-86=544
there would be 544 pens left
Answer:
m = (-3, 2) x = (-1)
Step-by-step explanation:
Just took this K12 test.
