All categories

3 years ago

Please need help I will be MARKING as BRIANILIST. thank you so much.

Mathematics

2 answers:

Arturiano [62]3 years ago

8 0

Answer:C.8.027

Step-by-step

V = s $^{3}$

The rate of change is found using the first derivative of this function. This is often called the gradient function, because it gives the gradient of a tangent line drawn at the specified point.

We now plug in s =6

jekas [21]3 years ago

7 0

<h2>Answer:</h2>

12.167(option D)

Solution,

$side \: length(s) = 2.3 \\ volume = {s}^{3} \\ \: \: \: \: \: \: \: \: \: \: = {(2.3)}^{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 2.3 \times 2.3 \times 2.3 \\ \: \: \: \: \: \: \: \: = 12.167 \: {cm}^{3} \\$

hope it helps...

Good luck on your assignment....

You might be interested in

please help. answer is 62.1m(squared) and the objects are composite! please show the work, no matter what i do i cant seem to ge

yuradex [85]

Answer:

$SA=62.1\ m^2$

Step-by-step explanation:

step 1

Find the surface area of the smaller rectangular prism

$SA=2B+Ph$

where

B is the area of the base

P is the perimeter of the base

h is the height of the prism

$SA=2[(2.5)(1.5)]+2(2.5+1.5)(1.5)$

$SA=7.5+12=19.5\ m^2$

step 2

Find the surface area of the cube

$SA=6s^2$

where

s is the length side of the cube

$SA=6(2.5^2)=37.5\ m^2$

step 3

Find the lateral area of the cylinder

$LA=\pi DL$

where

D is the diameter of the base

L is the length of cylinder

$LA=(3.14)(0.5)(3.5)=5.495\ m^2$

step 4

Find the area of the base of cylinder

$A=\pi r^{2}$

we have

$r=0.5/2=0.25\ m$ ----> the radius is half the diameter

$A=(3.14)(0.25)^{2}=0.19625\ m^2$

step 5

Find the surface are of the composite figure

we know that

The surface area of the composite figure is equal to the surface area of the smaller rectangular prism plus the lateral area of the cylinder, plus the surface area of the cube, minus the area of the two bases of cylinder

$SA=19.5+5.495+37.5-2(0.19625)=62.1\ m^2$

5 0

3 years ago

The Nelson Company makes the machines that automatically dispense soft drinks into cups. Many national fast food chains such as

Vika [28.1K]

Answer:

a) There is a 2.28% probability that a new cup will overflow when filled by the automatic dispenser.

b) The mean amount dispensed by the machine should be set at 16.14 ounces to satisfy this wish.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Normal model with mean 16 ounces and standard deviation 0.31 ounces. This means that $\mu = 16, \sigma = 0.31$ .

A new 16-ounce cup that is being considered for use actually holds 16.62 ounces of drink.

a. What is the probability that a new cup will overflow when filled by the automatic dispenser?

This probability is 1 subtracted by the pvalue of Z when $X = 16.62$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{16.62 - 16}{0.31}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772. This means that there is a 1-0.9772 = 0.0228 = 2.28% probability that a new cup will overflow when filled by the automatic dispenser.

b. The company wishes to adjust the dispenser so that the probability that a new cup will overflow is .006. At what value should the mean amount dispensed by the machine be set to satisfy this wish?

This is the value of $\mu$ , with $X = 16.62$ when Z has a pvalue of 0.94. It is between $Z = 1.55$ and $Z = 1.56$ , so we use $Z = 1.555$ .