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We have 10 ml of 20% acid to which we need to add "x" milliliters of 100% acid to make 50% acid.
.20 * 10 + 1.00x = .50 * (10 +x)
in which "x" is the volume of the 100% acid to be added.
2 + x = 5 + .5 x
.5x = 3
x = 6 milliliters
Source:
http://www.1728.org/mixture.htm
Scroll down to problem B
Answer:
The system is:
x + y = 8
x - y = -14
And the solution is:
x = -3
y = 11
Step-by-step explanation:
We have two numbers x and y, such that:
x + y = 8 (the sum is equal to 8)
x - y = -14 (the difference is equal to -14)
This is the system of equations we need to solve.
To solve the system, we first need to isolate one of the variables in one of the equations, I will isolate x in the first equation:
x = 8 - y
Now we can replace this in the other equation to get:
(8 - y) - y = -14
8 - 2*y = -14
8 + 14 = 2*y
22 = 2*y
22/2 = y
11 = y
Now we can replace this in the equation "x = 8 - y"
To get:
x = 8 - 11 = -3
Then the solution to the system is:
x = -3 and y = 11
1/10 is the next fraction in the sequence. If you multiply the numerator and denominator by a common factor to give each fraction a denominator of 20, the pattern goes 6/20, 5/20, 4/20, 3/20. The next term would be 2/20 which equals 1/10.
