How do you solve y=5/8b + 10 for b

Mathematics

1 answer:

joja [24]3 years ago

5 0

Answer:

b = $\frac{8y-80}{5}$

Step-by-step explanation:

Given

y = $\frac{5}{8}$ b + 10

Multiply through by 8 to clear the fraction

8y = 5b + 80 ( subtract 80 from both sides )

8y - 80 = 5b ( divide both sides by 5 )

$\frac{8y-80}{5}$ = b

You might be interested in

Two lines or equations are described in each part. Decide whether each system has one solution, no solution, or infinitely many

olga55 [171]

To get the solution of a set of equations means to get a point that satisfies both equations.

Part (1):
The first line has a rate of change of 7, this means that slope of first line is 7
The second line has a rate of change of -7, this means that slope of second line is -7
Since the slope of the first line = - slope of the second line, then these two lines are definitely perpendicular to each other.
Two perpendicular lines will meet only in one point. This means that one point only will satisfy both equations (check the image showing perpendicular lines attached below)
Therefore, only one solution exists in this case

Part (2):
The first given equation is:
2x + 3y = 5.5
The second given equation is:
4x + 6y = 11
If we simplified the second equation we will get: 2x + 3y = 5.5 which is exactly similar to the first equation.
This means that the two given equations represent the same line.
Therefore, we have infinite number of solutions

Part (3):
We are given that the two lines are parallel. This means that the two lines are moving the same path side by side. Two parallel lines can never intersect. This means that no point can satisfy both equations (check the image showing parallel lines attached below).
Therefore, we have no solutions for this case.