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4 years ago

How do you solve y=5/8b + 10 for b

Mathematics

1 answer:

joja [24]4 years ago

5 0

Answer:

b = $\frac{8y-80}{5}$

Step-by-step explanation:

Given

y = $\frac{5}{8}$ b + 10

Multiply through by 8 to clear the fraction

8y = 5b + 80 ( subtract 80 from both sides )

8y - 80 = 5b ( divide both sides by 5 )

$\frac{8y-80}{5}$ = b

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If f(x)=-7, then x=?

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Step-by-step explanation:

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3 years ago

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faltersainse [42]

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3 years ago

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Step-by-step explanation:

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For which k are the roots of k(x2+1)=x2+3x–3 real and distinct?

Ugo [173]

Answer:

The solution for k is the interval (-3.5,1.5)

Step-by-step explanation:

we have

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we know that

If the discriminant is greater than zero . then the quadratic equation has two real and distinct solutions

The discriminant is equal to

$D=b^{2}-4ac$

In this problem we have

a=(1-k)

b=3

c=-(3+k)

substitute

$D=3^{2}-4(1-k)(-3-k)\\ \\D=9-4(-3-k+3k+k^{2})\\ \\D=9+12+4k-12k-4k^{2}\\ \\D=21-8k-4k^{2}$

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solve the quadratic equation by graphing

The solution for k is the interval (-3.5,1.5)

see the attached figure

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3 years ago

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suter [353]

Answer:

- 836

Step-by-step explanation:

Check out the attachment below:

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3 years ago