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2 years ago

Janet has 6 coins worth 47cents

Mathematics

2 answers:

siniylev [52]2 years ago

8 0

1 quarter, 2 dimes, and 2 pennies.

galben [10]2 years ago

3 0

A quarter, two dimes, and two pennies.

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3/5y+5=7 what's the answer to this

sergij07 [2.7K]

The answer is y= $\frac{10}{3}$ Hope this helps

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2 years ago

Test 69,000 on hearing to for divisibility by 2 3 5 9 or 10

svetoff [14.1K]

Yes they are correct

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3 years ago

The solution to the equation x + 11 = 18 is x = 7.<br><br><br> True<br><br> False

Usimov [2.4K]

Answer:

True

Step-by-step explanation:

X+11=18

subtract 11 from both sides

18-11=7

x=7

5 0

2 years ago

Read 2 more answers

Examine the system of equations. y = 3 2 x − 6, y = −9 2 x + 21 Use substitution to solve the system of equations. What is the v

nadezda [96]

Answer:

Step-by-step explanation:

Given the system of equations y = 3/2 x − 6, y = −9/2 x + 21, since both expressions are functions of y, we will equate both of them to find the variable x;

3/2 x − 6 = −9/2 x + 21,

Cross multiplying;

3(2x+21) = -9(2x-6)

6x+63 = -18x+54

collecting the like terms;

6x+18x = 54-63

24x = -9

x = -9/24

x = -3/8

To get the value of y, we will substitute x = -3/8 into any of the given equation. Using the first equation;

y = 3/2x-6

y = 3/{2(-3/8)-6}

y = 3/{(-3/4-6)}

y = 3/{(-3-24)/4}

y = 3/(-27/4)

y = 3 * -4/27

y = -4/9

Hence, the value of y is -4/9

4 0

2 years ago

Read 2 more answers

There are six balls in the bag. Two are basketballs, three are playground balls, and one is a soccer ball. What is the probabili

aleksandr82 [10.1K]

Answer:

$\frac{1}{6}=0.16$

Step-by-step explanation:

Given : There are six balls in bag

Basketballs=2

Playground balls =3

Soccer ball =1

To Find : the probability that if you pick one of the balls without looking, it will be a soccer ball

Solution :

Total no. of balls = 6

No. of soccer balls = 1

Probability = favorable outcomes / total outcomes

Since total outcomes = total no. of balls =6

And favorable outcome = no. of soccer balls = 1

Thus , Probability of getting soccer ball = $\frac{1}{6}$

Hence the probability that if you pick one of the balls without looking, it will be a soccer ball:

$\frac{1}{6}=0.16$

7 0

3 years ago