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Lubov Fominskaja [6]
3 years ago
6

Please Help ASAP!! Will give BRANLIEST!! f(x)=16 f(4)=3x+5 g(x)=2x^2-4 h(x) = -3x-9

Mathematics
2 answers:
sdas [7]3 years ago
8 0
The answer is 91 djsjsjsjsj
Nata [24]3 years ago
7 0

Answer:

it equals 91

Step-by-step explanation:

which is ur answer and yw :)

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juin [17]

Answer:

Original Price= $20

Sales Price= $20*0.80= $16

8 0
3 years ago
Please help on question 4.<br> (Questions 1, 2, and 3 have been answered.)
ss7ja [257]

Answer:

Step-by-step explanation:

So, the longest tooth is 4 3/4 and the shortest is 3 1/4. So if you subtract 4 3/4 - 3 1/4, you will get the answer 1 2/4, which you can simplify to 1 1/2 or 1.5 :)

6 0
3 years ago
I need hellllppp plsssss​
bagirrra123 [75]

Answer:

a_7=-15

Step-by-step explanation:

a_n  is given as the nth term of a sequence.

We want to find a_7 , which means we find the 7th term of the sequence.

Here, we simply substitute "7" into "n" of the formula given for  a_n  to find the value of the 7th term of the sequence.

We show this below:

a_n=-3(n-2)\\a_7=-3(7-2)\\a_7=-3(5)\\a_7=-15

So the 7th term is "-15"

6 0
3 years ago
What is another way to write 300+20+5
Aleks04 [339]
325 you will get as your answer
3 0
4 years ago
Read 2 more answers
An exponential function f(x)
natka813 [3]

Given:

An exponential function f(x)=ab^x passes through the points (0, 12000) and (2, 3000).

To find:

The values of a and b.

Solution:

We have,

f(x)=ab^x      ...(i)

It passes through the point (0,12000). Putting x=0 and f(x)=12000 in (i), we get

12000=ab^0

12000=a(1)

12000=a

Given function passes through the point (2,3000). Putting x=2, a=12000 and f(x)=3000 in (i), we get

3000=12000b^2

\dfrac{3000}{12000}=b^2

\dfrac{1}{4}=b^2

Taking square root on both sides.

\pm \dfrac{1}{2}=b

For an exponential function b cannot be negative. So, b=\dfrac{1}{2}.

Therefore, the value of a is 12000 and the value of b is \dfrac{1}{2}.

3 0
3 years ago
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