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AlladinOne [14]
3 years ago
6

Which of the following statements must be true about this diagram? check all that apply.

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0
I believe z>x if I’m wrong let me know
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What are the solutions to the quadratic equation x2 – 16 = 0?
exis [7]

Answer:

2nd choice: x=4 and x=-4

Step-by-step explanation:

x^2 - 16 = 0 can be simplified to (x-4)(x+4)=0

x-4 = 0 so x = 4

and x + 4 = 0 so x = -4

4 0
3 years ago
Read 2 more answers
Allen is showing us work in simplifying – 8.3+9.2-4.4+3.7 point identify and explain any errors in his work in or in his reasoni
vladimir1956 [14]

Answer: -8.3 + 9.2 - 4.4 + 3.7

= -8.3 + 9.2 + (-4.4) + 3.7            {Additive inverse}

= -8.3 + (-4.4) + 9.2 + 3.7            {Commutative Property}

= [ -8.3 + (-4.4] + [ 9.2 + 3.7]       {Associative property}

=  - 12.7 + 12.9

= 0.2

Step-by-step explanation: I copied it from someone hope it helps though! :D

5 0
3 years ago
The maths test scores of 280 students are shown in the histogram below. Find the median score Find the lower quartile of the sco
cestrela7 [59]

Answer:

115 is the score

Step-by-step explanation:

4 0
3 years ago
Find the volume of a cylinder that has a radius of 6 feet and a height of 10 feet. Use 3.14 for pi
dybincka [34]
V = pi r^2 h
= pi (36)(10)
6 0
3 years ago
true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp
Goshia [24]

Answer:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

6 0
3 years ago
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