This is timed and Will mark BRAINLIEST!!!

A chef at a restaurant uses 13 pounds of butter each day.About how many grams of butter does the chef use each day us 16ounces/1

lesantik [10]

Answer:

5907.2 grams

Step-by-step explanation:

16 x 28.4 x 13 = 5907.2grams

6 0

2 years ago

When dealing with word problems and linear equations, what does the y-intercept represent and how is the slope defined?

katovenus [111]

Answer:

C

Step-by-step explanation:

y-intercept represents the starting value, slope is the rate of change

slope is rise/run

6 0

3 years ago

Read 2 more answers

A circus tent is cylindrical upto a height of 3.3 m and conical above it if the diameter of the base is 100m and slant height of

Rina8888 [55]

Total cost of canvas required in making the tent is rupees 79128

Solution:

Given:

Height of the cylindrical tent = h = 3.3 m

Diameter of it's base = d = 100m

$radius = \frac{diameter}{2} = \frac{100}{2} = 50$

r = 50 m

Curved surface area of cylinder:

$C.S.A = 2 \pi rh$

$C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2$

Thus Curved surface area of cylinder = 1036.2 square meter

Curved surface area of cone:

$C.S.A = \pi rl$

$C.S.A = 3.14 \times 50 \times 56.4 = 8854.8$

Thus Curved surface area of cone = 8854.8 square meter

Total curved area of tent:

⇒ curved area of cone + curved area of cylinder

$\rightarrow 8854.8 + 1036.2=9891$

Thus total curved area of tent = 9891 square meter

find total cost of canvas required in making the tent:

The cost of canvas is 8 rupees per square meter

$\rightarrow \text{total cost } = 9891 \times 8 = 79128$

Thus total cost of canvas required in making the tent is rupees 79128

7 0

2 years ago

The ratio of red jelly beans to yellow jelly beans in a dish is 3:4. If Greg eats 3 red jelly beans and 6 yellow ones, the ratio

slava [35]

Answer:

63

Step-by-step explanation:

3×9= 27

4×9= 36

27+36= 63

7 0

3 years ago

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 12 feet a

Brrunno [24]

Answer:

Step-by-step explanation:

The student needs to check all algebraic and mathmatical calculations for errors and typos. I'm old and have been prone to making mistakes.

Cylinder A DIAMETER 12 ft and Height 13 ft

Cylinder B DIAMETER 10 ft and Height 16 ft

After pumping How much water remains in cylinder A

Volume of a cylinder = π(radius)²h is the normal form since they provided the diameter I will use Volume of a cylinder = π(diameter/2)²h

Water remaining in A = Volume of A - Volume of B =

VolA - VolB = π(D for A/2)²H of A - π(D for B/2)²H of B

writing if a little more condensed

VolA - VolB = π(D for A/2)²H of A - π(D for B/2)²H of B

Va - Vb = π(Da/2)²Ha - π(Db/2)²Hb

= π [(Da²/2²)Ha - (Db²/2²)Hb] factored out the π

= π/4 [ Da²Ha - Db²Hb] factored out the (1/2)²

I can't think of any other algebraic steps

Va - Vb = Water Remaining in Container A = π/4 [ Da²Ha - Db²Hb]

= π/4 [ (12²)(13) - (10²)(16)]

= π/4 [ (144)(13) - (100)(16)]

= π/4 [ 1872 - 1600 ]

= π/4 [272]

= π [ 272/4 ]

= π [ 136 / 2]

= π [ 68 ]

= π (68)

= 213.6 ft³ rounded to the nearest tenth

I checking my answer by using V = πr²h r = d/2

Va - Vb = π [ra²ha - rb²hb]

= π [6²(13) - 5²(16)]

= π [(36)(13) - (25)(16)]

= π [ 468 - 400]

= 68 π

= 213.6 ft³ I got the same answer

= π

test

8 0

3 years ago