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3 years ago

This is timed and Will mark BRAINLIEST!!!

Mathematics

1 answer:

sertanlavr [38]3 years ago

5 0

answer is either A or D

I hope this help. but I'm not really sure.

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Explain step by step how to solve problem 114÷6114÷6

Serhud [2]

tell you teacher to Fu** off

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3 years ago

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Factor completely 4ab − 7ax + 8b − 14x.

ASHA 777 [7]

4ab + 7ax + 8b - 14x
a(4b - 7x) + 2(4b - 7x)
(4b - 7x)(a + 2)

The answer is: (4b - 7x)(a + 2).

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3 years ago

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AVERE<br> Given: P(0, -13) and 7(15,-7)<br> What is the slope of PT?

Fynjy0 [20]

Answer:

2/5

Step-by-step explanation:

To find the slope of a line segment, find the difference in y and divide by the difference in x (delta y / delta x)

Delta y: -7 - (-13) = 6

Delta x: 15 - 0 = 15

Slope = delta y / delta x

Slope = 6/15 = 2/5

If this helped, I really would appreciate if you tagged as brainliest!

8 0

2 years ago

Use the formula C(n, x)pxqn − x to determine the probability of the given event. (Round your answer to four decimal places.) The

miskamm [114]

Answer: 0.1334

Step-by-step explanation:

Given

There are seven trails with a probability of success is $p=\frac{1}{4}$

$\therefore q=1-p\\q=1-\frac{1}{4}\\q=\frac{3}{4}$

Using the binomial distribution, the Probability of exactly no success i.e. x=0 is given by

$\Rightarrow ^7C_0\cdot p^0 \cdot q^{7-0}\\\Rightarrow 1\times(\frac{1}{4})^0 \cdot (\frac{3}{4})^7\\\Rightarrow 1\times 1 \cdot (0.75)^7\\\Rightarrow 0.1334$

7 0

3 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

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