Median and IQR are the most appropriate measures of center and spread for this data set.
<h3>Why are
Median and IQR the most appropriate?</h3>
Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:
- Mean is affected by extreme values
- Mean is not correct if more outliers are present
- Mean may not represent the nature of the data whether skewed right or left.
Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,
Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.
Therefore, Option B is correct.
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the first option is the answer
Step-by-step explanation:
4c + 6a <= 120 [building hours]
4c + 4a <= 100 [testing hours]
4 * 20 + 6 * 6 <= 120
80 + 36 <= 120
116 <= 120
true, they have enough building hours
4 * 20 + 4 * 6 <= 100
80 + 24 <= 100
104 <= 100
false, they won't have enough testing hours
the first option is the answer
We have that
we know that
Is the equation of a vertical parabola open down
so
the vertex is a maximum
step 1
convert the equation of the parabola in the vertex form
the vertex (h,k) is the point (0,36)
Part a) The point on the graph where the height of the tunnel is a maximum is (0,36)
Part b) The points on the graph where the height of the tunnel is zero feet is when y=0
so
for y=0
the points are (-6,0) and (6,0)
see the attached figure
Answer:
- perimeter: 56 units
- area: 192 square units
Step-by-step explanation:
We assume you're interested in the convex polygon, so the given vertices are <em>not</em> listed in order around the figure.
The figure is 12 units by 16 units, so has a perimeter of ...
P = 2(L +W)
P = 2(16 +12) = 56 . . . . units
and an area of ...
A = LW
A = (16)(12) = 192 . . . . square units