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elena-s [515]
3 years ago
15

A bag of candy that weighs 3.48 kg is divided equally.there is enough candy for 7.25 piles.what is the weight of the candy in ea

ch pile
Mathematics
1 answer:
alekssr [168]3 years ago
8 0
So 3.38 kg are divided into 7.25 piles
3.38 / 7.25
That is 0.466
Each pile, rounded to the nearest hundredth, is about 0.47 kg. 
That is about 1 pound each pile

Hope this helps :)
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Can someone answer this for me? Thanks a bunch!
bija089 [108]
What is the question????
7 0
3 years ago
Read 2 more answers
Pls help these are test corrections
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Answer:

See explanation

Step-by-step explanation:

Given triangle has its vertices at points A(-4,-2), B(1,3) and C(3,-2).

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AC=\sqrt{(-4-3)^2+(-2-(-2))^2}=\sqrt{(-7)^2+(0)^2}=\sqrt{49+0}=\sqrt{49}=7\ units\\ \\AB=\sqrt{(-4-1)^2+(-2-3)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=5\sqrt{2}\ units\\ \\BC=\sqrt{(1-3)^2+(3-(-2))^2}=\sqrt{(-2)^2+(5)^2}=\sqrt{4+25}=\sqrt{29}\ units

The longest side is AB.

By the Pythagorean theorem,

AB^2=AC^2+BC^2\\ \\(5\sqrt{2})^2=7^2+\sqrt{29}^2\\ \\50=49+29\\ \\50=78

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