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3 years ago

Solve the following equation for the variable a 2a+b=c-4d

Mathematics

2 answers:

Archy [21]3 years ago

8 0

Answer:

The value of the equation is $a=\frac{c-4d-b}{2}$ .

Step-by-step explanation:

Consider the provided equation.

$2a+b=c-4d$

We need to solve the provided equation for a.

Subtract b from both side.

$2a+b-b=c-4d-b$

$2a=c-4d-b$

Divide both sides by 2.

$\frac{2a}{2}=\frac{c-4d-b}{2}$

$a=\frac{c-4d-b}{2}$

Hence, the value of the equation is $a=\frac{c-4d-b}{2}$ .

Natasha_Volkova [10]3 years ago

6 0

2a+b=c-4d
a= c-4d-b/2

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Step-by-step explanation:

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The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

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